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Chemistry • Class 11

Thermodynamics - Class 11 Part 1

Master Chemical Thermodynamics through focused practice that strengthens conceptual understanding, problem-solving skills, and the ability to recognize common traps and misconceptions. Explore challenging questions designed to develop deeper reasoning and confident application of key ideas.

Overview

This chapter explores the principles of thermodynamics, energy transformations, state functions, and their significance in chemical processes.

Why This Chapter Matters

  • Learning thermodynamics helps students understand energy flow in chemical reactions, the efficiency of systems, and real-world applications like engines and refrigeration.

Real-Life Applications

  • Understanding energy conversion in chemical and physical processes.
  • Exploring how thermodynamics principles apply to engines and refrigeration systems.
  • Learning how entropy and free energy determine the spontaneity of reactions.

Skills You Will Learn

  • Applying the first and second laws of thermodynamics.
  • Understanding enthalpy, entropy, and Gibbs free energy changes in chemical reactions.
  • Solving numerical problems related to heat, work, and internal energy.

Core Concepts to Master

State vs Path Functions

Differentiate by path independence; trap lies in assuming heat and work are properties rather than process-dependent quantities.

IUPAC Sign Convention

Work done BY system is negative, ON system is positive; sign errors here invalidate the entire First Law calculation.

Reversible Expansion Work

Use integration PdV only for reversible processes; students erroneously apply this to irreversible expansion against constant external pressure.

First Law Consistency

Delta U = q + w is universal; never ignore sign conventions for q and w when calculating internal energy changes.

Enthalpy Definition

H = U + PV; recognize that Delta H equals heat at constant pressure, not constant volume conditions.

Heat Capacity Ratio

Cp - Cv = R is only for ideal gases; using it for solids or liquids is a common conceptual failure.

Adiabatic Free Expansion

In vacuum expansion, w=0 and q=0, hence Delta U=0; students often miscalculate work done against zero pressure.

Hess's Law Application

Treat thermochemical equations as algebraic sums; trap is failing to multiply Delta H when stoichiometric coefficients are changed.

Bond Enthalpy Pitfall

Delta H = sum(Reactant bonds) - sum(Product bonds); ignore non-gas phase states at your peril.

Spontaneity Criteria

Delta G < 0 for spontaneity; ensure entropy change is of the 'universe', not just the system.

Entropy of Phase Change

At equilibrium (melting/boiling), Delta G = 0, so Delta S = Delta H / T; trap is using non-equilibrium temperatures.

Third Law Application

Perfect crystals at 0K have zero entropy; do not assume entropy is zero at any other temperature or state.

Gibbs-Helmholtz Equation

Delta G = Delta H - T*Delta S; spontaneity depends on the sign and magnitude of T relative to enthalpy/entropy ratios.

Standard State Conditions

Standard state implies 1 bar pressure; ignore molarity-based standard states unless dealing specifically with aqueous solutions.

Internal Energy of Real Gases

Internal energy depends on temperature and intermolecular forces; for real gases, it is not solely a function of temperature.

Concept Collisions Used by Examiners

Competitive examinations rarely assess concepts in isolation. Instead, examiners intentionally combine multiple concepts from this and related chapters to create higher-order questions that test conceptual reasoning, analytical thinking, and problem-solving ability. The concept collision patterns below represent the combinations most frequently used while designing questions for this chapter.

State vs Path Functions
Concentration Units Dependency
Vapor Pressure Lowering (Mole Fraction)
State vs Path Functions
Gibbs Energy and Spontaneity
Temperature Coefficient (Q10)
State vs Path Functions
Internal Energy of Real Gases
Graphical Slopes Analysis
State vs Path Functions
Standard Electrode Potential Sign Conventions
Degree of Dissociation (Alpha)
State vs Path Functions
Stoichiometric Coefficient Division
Reaction Quotient vs. Equilibrium Constant
IUPAC Sign Convention
Bond Enthalpy Pitfall
Bond Cleavage Energetics
IUPAC Sign Convention
Fractional Oxidation State Misconception
KMnO₄ Redox pH Dependency
IUPAC Sign Convention
Reaction Quotient vs. Equilibrium Constant
Nernstian Redox Equilibrium
Reversible Expansion Work
Gibbs-Helmholtz Equation
Nernstian Redox Equilibrium
Reversible Expansion Work
Internal Energy of Real Gases
Reversible Expansion Work
Spontaneity Criteria
Le Chatelier’s Principle: Inert Gas Addition
Reversible Expansion Work
Units of Rate Constant (k)
Acid-Catalyzed Hydration Mechanism
Esterification Reversibility
First Law Consistency
First Law Consistency
Fuel Cell Efficiency
Electrode Potential Sign Conventions
Hess's Law Application
E° (M²⁺/M) Anomalies
Standard State Conditions
Enthalpy Definition
Boiling Point Elevation (Solvent vs Solution)
Solubility of Solids in Liquids
Enthalpy Definition
Bond Cleavage Energetics
Resonance Energy and Stability
Enthalpy Definition
SN1 Carbocation Rearrangement
Hyperconjugation Logic
Enthalpy Definition
Variable Oxidation State Stability
Stability of High OS Fluorides/Oxides
Heat Capacity Ratio
Entropy of Phase Change
Steady State Approximation
Adiabatic Free Expansion
Arrhenius Pre-exponential Factor
Adiabatic Free Expansion
Concentration Cells
Nernst Equation Concentration Dependence
Adiabatic Free Expansion
Electrode Potential Dependencies
Adiabatic Free Expansion
Le Chatelier’s Principle: Inert Gas Addition
Hess's Law Application
Bond Enthalpy Pitfall
Variable Oxidation State Stability
Hess's Law Application
Comproportionation Reversibility
Oxidation State Extremes
Hess's Law Application
Disaccharide Hydrolysis Products
Nitrogenous Base Keto-Enol Tautomerism
Hess's Law Application
Electrolysis Product Prediction
E° (M²⁺/M) Anomalies
Hess's Law Application
SN1 Carbocation Rearrangement
Hyperconjugation Logic
Bond Enthalpy Pitfall
E° (M²⁺/M) Anomalies
Bond Enthalpy Pitfall
Grignard Reagent Sensitivity
Bond Enthalpy Pitfall
Standard State Conditions
Bond Enthalpy Pitfall
State vs Path Functions
First Law Consistency
Spontaneity Criteria
Activation Energy Trap
Steady State Approximation
Spontaneity Criteria
Electrode Potential Sign Conventions
Concentration Units Dependency
Spontaneity Criteria
Enthalpy Definition
Standard State Conditions
Spontaneity Criteria
Ligand Denticity Variations
Complex Ion Oxidation States
Spontaneity Criteria
Van’t Hoff Factor (i) Application
Degree of Dissociation/Association
Entropy of Phase Change
E° (M²⁺/M) Anomalies
Entropy of Phase Change
Van’t Hoff Factor (i) Application
Third Law Application
Ambidentate Linkage Isomerism
Third Law Application
Boiling Point Elevation (Solvent vs Solution)
Third Law Application
D-Glucose Anomeric Equilibrium
Gibbs-Helmholtz Equation
Degree of Dissociation (α) approximation
Molecular Mass Abnormalities
Gibbs-Helmholtz Equation
Enthalpy Definition
Hess's Law Application
Gibbs-Helmholtz Equation
Gibbs Energy and Spontaneity
Corrosion as Electrochemical Process
Gibbs-Helmholtz Equation
Salt Hydrolysis Logic
Acidity and Basicity (pKa/pKb)
Standard State Conditions
Carboxylic Acid Strength
Inductive Effect (I-Effect)
Standard State Conditions
Crystal Field Splitting (Octahedral)
Werner’s Theory Postulates
Standard State Conditions
Electrode Potential Sign Conventions
Fuel Cell Efficiency
Standard State Conditions
Pseudo-First Order Kinetics
Activation Energy Trap
Standard State Conditions
Raoult’s Law Ideal vs Non-Ideal
Van’t Hoff Factor (i) Application
Internal Energy of Real Gases
Reversible Expansion Work
IUPAC Sign Convention

Exam Coverage

Understand how this chapter is tested across major competitive examinations.

JEE Advanced

India · Competitive Exam · Undergraduate

JEE Main

India · Competitive Exam · Undergraduate

BITSAT

India · Competitive Exam · Undergraduate

NEET-UG

India · Competitive Exam · Undergraduate

IISER Aptitude Test (IAT)

India · Competitive Exam · Undergraduate

NEST

India · Competitive Exam · Undergraduate

NSEC

India · Olympiad · High School

AP Chemistry

United States · Curriculum · Advanced Placement

A-Level Chemistry

United Kingdom · Curriculum · Advanced Level

IB Chemistry HL

International · Curriculum · IB Diploma

Singapore A-Level Chemistry

Singapore · Curriculum · Advanced Level

Cambridge International A-Level Chemistry

International · Curriculum · Cambridge

International Chemistry Olympiad (IChO)

International · Olympiad · International

Practice Questions

Strengthen your understanding by solving carefully selected questions from this chapter.

50 Questions
1

Consider a galvanic cell operating at 300 K300\text{ K} with the following balanced cell reaction:

\ceM(s)+X2+(aq)<=>M2+(aq)+X(s)\ce{M(s) + X^{2+}(aq) <=> M^{2+}(aq) + X(s)}

The standard cell potential at 300 K300\text{ K} is E∘=0.10 VE^{\circ} = 0.10\text{ V}. The temperature coefficient of the standard cell potential at constant pressure is (∂E∘∂T)P=−5.0×10−4 V K−1\left(\frac{\partial E^{\circ}}{\partial T}\right)_P = -5.0 \times 10^{-4}\text{ V K}^{-1}.

Assuming that the standard enthalpy (ΔH∘\Delta H^{\circ}) and standard entropy (ΔS∘\Delta S^{\circ}) of the reaction are independent of temperature, determine the standard enthalpy of the reaction at 300 K300\text{ K} and the temperature (TeqT_{eq}) at which the cell reaction reverses its direction of spontaneity under standard conditions.

(Given: Faraday's constant F=96500 C mol−1F = 96500\text{ C mol}^{-1})

2

A 0.1 M0.1\text{ M} aqueous solution of a weak monoprotic acid, \ce{HA}, exhibits an osmotic pressure of 2.75 atm2.75\text{ atm} at 300 K300\text{ K} and 3.60 atm3.60\text{ atm} at 360 K360\text{ K}. Assuming the volume of the solution is independent of temperature, calculate the standard enthalpy of dissociation (ΔH∘\Delta H^\circ) of the acid in kJ/mol\text{kJ/mol}.

[Given: R=112 L atm K−1 mol−1R = \frac{1}{12}\text{ L atm K}^{-1}\text{ mol}^{-1} for osmotic pressure, R=8.3 J K−1 mol−1R = 8.3\text{ J K}^{-1}\text{ mol}^{-1} for thermodynamic calculations. ln⁡(2)=0.70\ln(2) = 0.70, ln⁡(3)=1.10\ln(3) = 1.10, ln⁡(4.5)=1.50\ln(4.5) = 1.50]

3

Consider the gas-phase synthesis reaction at 300 K300\text{ K}:

\ceA(g)+2B(g)−>C(g)\ce{A(g) + 2B(g) -> C(g)}

The standard thermodynamic parameters at 300 K300\text{ K} are provided below:

SpeciesΔHf∘ (kJ mol−1)Sm∘ (J K−1mol−1)Cp,m∘ (J K−1mol−1)\ceA(g)2025050\ceB(g)1015040\ceC(g)035030\begin{array}{|c|c|c|c|} \hline \text{Species} & \Delta H^\circ_f \text{ (kJ mol}^{-1}\text{)} & S^\circ_m \text{ (J K}^{-1}\text{mol}^{-1}\text{)} & C^\circ_{p,m} \text{ (J K}^{-1}\text{mol}^{-1}\text{)} \\ \hline \ce{A(g)} & 20 & 250 & 50 \\ \ce{B(g)} & 10 & 150 & 40 \\ \ce{C(g)} & 0 & 350 & 30 \\ \hline \end{array}

Assuming the molar heat capacities at constant pressure (Cp,m∘C^\circ_{p,m}) are independent of temperature, determine the standard Gibbs free energy change (ΔG∘\Delta G^\circ) for the reaction at 500 K500\text{ K}.

(Given: ln⁡(5/3)=0.51\ln(5/3) = 0.51)

4

The standard enthalpy of ionization of a weak monoprotic acid \ce{HA} is ΔHion∘=54.45 kJ mol−1\Delta H^\circ_{\text{ion}} = 54.45 \text{ kJ mol}^{-1} and is assumed to be independent of temperature. At 298 K298 \text{ K}, the acid dissociation constant is Ka=1.0×10−5K_a = 1.0 \times 10^{-5}. The ionic product of water at 318 K318 \text{ K} is Kw=2.5×10−14K_w = 2.5 \times 10^{-14}. Calculate the pH of a 0.1 M0.1 \text{ M} aqueous solution of the sodium salt \ce{NaA} at 318 K318 \text{ K}.

(Given: R=8.314 J K−1 mol−1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1}, 2.303×R=19.15 J K−1 mol−12.303 \times R = 19.15 \text{ J K}^{-1} \text{ mol}^{-1}, log⁡2.5=0.4\log 2.5 = 0.4)

5

Given the standard reduction potentials at 298 K298\text{ K}: E\ceCu+/Cu∘=+0.52 VE^\circ_{\ce{Cu^+/Cu}} = +0.52\text{ V} E\ceCu2+/Cu+∘=+0.16 VE^\circ_{\ce{Cu^{2+}/Cu^+}} = +0.16\text{ V} And the overall formation constants (β\beta) for copper-ammonia complexes: β2 for \ce[Cu(NH3)2]+=1011\beta_2 \text{ for } \ce{[Cu(NH_3)_2]^+} = 10^{11} β4 for \ce[Cu(NH3)4]2+=1013\beta_4 \text{ for } \ce{[Cu(NH_3)_4]^{2+}} = 10^{13} Consider the comproportionation reaction in an aqueous medium where the equilibrium concentration of free \ceNH3\ce{NH_3} is maintained at 1.0 M1.0\text{ M}: \ceCu(s)+[Cu(NH3)4]2+(aq)⇌2[Cu(NH3)2]+(aq)\ce{Cu(s) + [Cu(NH_3)_4]^{2+}(aq) \rightleftharpoons 2[Cu(NH_3)_2]^+(aq)} Which of the following correctly identifies the standard potential of this reaction (Erxn∘E^\circ_{\text{rxn}}) under these conditions and the thermodynamic stability of the \ceCu(I)\ce{Cu(I)} state? (Take 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06\text{ V})

6

The standard Gibbs free energy of dissociation (ΔGdiss∘\Delta G^\circ_{diss}) for acetic acid (\ceCH3COOH\ce{CH3COOH}) and pivalic acid (\ce(CH3)3CCOOH\ce{(CH3)3CCOOH}) are evaluated at 298 K298\text{ K} in two different media: Water (ϵ=78.4\epsilon = 78.4) and the Gas Phase (ϵ=1\epsilon = 1). Let ΔΔGaq∘=ΔGdiss,aq∘(pivalic)−ΔGdiss,aq∘(acetic)\Delta \Delta G^\circ_{aq} = \Delta G^\circ_{diss, aq}(\text{pivalic}) - \Delta G^\circ_{diss, aq}(\text{acetic}) and ΔΔGgas∘=ΔGdiss,gas∘(pivalic)−ΔGdiss,gas∘(acetic)\Delta \Delta G^\circ_{gas} = \Delta G^\circ_{diss, gas}(\text{pivalic}) - \Delta G^\circ_{diss, gas}(\text{acetic}). Which of the following correctly identifies the signs of ΔΔGaq∘\Delta \Delta G^\circ_{aq} and ΔΔGgas∘\Delta \Delta G^\circ_{gas}, and the dominant physical phenomenon dictating the gas-phase thermodynamic trend?

7

The specific acid-catalyzed hydrolysis of ethyl acetate in a dilute aqueous \ceHCl\ce{HCl} solution follows the rate law: Rate=k[Ester][\ceH+][\ceH2O]\text{Rate} = k[\text{Ester}][\ce{H+}][\ce{H2O}], where kk is the true third-order rate constant. The rate constant kk follows the Arrhenius equation with an activation energy parameter Ea2.303R=3000 K\frac{E_a}{2.303 R} = 3000 \text{ K}.

The reaction is studied at two different temperatures, 300 K300 \text{ K} and 375 K375 \text{ K}, in a variable-volume reactor maintained at a pressure sufficient to keep the mixture entirely in the liquid state. The density of the reaction mixture is 1.00 g mL−11.00 \text{ g mL}^{-1} at 300 K300 \text{ K} and drops to a hypothetical value of 0.80 g mL−10.80 \text{ g mL}^{-1} at 375 K375 \text{ K}.

If kobsk_{obs} is the observed pseudo-first order rate constant (defined by Rate=kobs[Ester]\text{Rate} = k_{obs}[\text{Ester}]), determine the ratio kobs(375 K)kobs(300 K)\frac{k_{obs}(375 \text{ K})}{k_{obs}(300 \text{ K})}.

(Assume the total mass of the mixture and the moles of the acid catalyst remain constant, and the ester is present in trace amounts.)

8

Consider the following ligand exchange reaction for a \ce{Ni^{2+}} (d8d^8) complex in aqueous solution at 300 K300 \text{ K}:

\ce[Ni(A)6]2+(aq)+3B(aq)<=>[Ni(B)3]2+(aq)+6A(aq)\ce{[Ni(A)6]^{2+}(aq) + 3B(aq) <=> [Ni(B)3]^{2+}(aq) + 6A(aq)}

where A is a neutral monodentate ligand and B is a neutral bidentate ligand.

The crystal field splitting energy (Δo\Delta_o) for \ce{[Ni(A)6]^{2+}} is 150 kJ mol−1150 \text{ kJ mol}^{-1} and for \ce{[Ni(B)3]^{2+}} is 120 kJ mol−1120 \text{ kJ mol}^{-1}. Assume that the standard enthalpy change (ΔH∘\Delta H^\circ) of the exchange reaction is determined entirely by the difference in Crystal Field Stabilization Energy (CFSE) between the two complexes.

If the standard entropy change (ΔS∘\Delta S^\circ) for the exchange reaction is +140 J K−1 mol−1+140 \text{ J K}^{-1} \text{ mol}^{-1}, calculate the standard Gibbs free energy change (ΔG∘\Delta G^\circ) and identify the thermodynamically more stable complex at 300 K300 \text{ K}.

9

A 0.10 mol kg−10.10 \text{ mol kg}^{-1} aqueous solution of a weak monoprotic acid \ce{HA (aq)} freezes at −0.2232∘C-0.2232^\circ\text{C} at 1 atm1 \text{ atm}. The cryoscopic constant of water is Kf=1.86 K kg mol−1K_f = 1.86 \text{ K kg mol}^{-1}. Assume the solution behaves ideally with respect to the solvent (osmotic coefficient ϕ=1\phi = 1), such that the freezing point depression is strictly proportional to the total molality of all solute particles. However, the acid dissociation equilibrium is non-ideal. If the mean ionic activity coefficient of the ions \ce{H+ (aq)} and \ce{A- (aq)} in this solution is γ±=0.80\gamma_{\pm} = 0.80 and the activity coefficient of the unionized acid is γHA=1.0\gamma_{HA} = 1.0, what is the true thermodynamic acid dissociation constant (Ka∘K_a^\circ) of \ce{HA} at the freezing point?

10

nn moles of a real gas obeying the van der Waals equation of state undergoes a reversible isothermal expansion from an initial volume V1V_1 to a final volume V2V_2 at a constant temperature TT. Which of the following expressions correctly represents the change in internal energy (ΔU\Delta U) and the heat absorbed (qq) by the gas? (Given: aa and bb are van der Waals constants)

11

Consider the elementary reversible gas-phase reaction \ceA(g)<=>B(g)\ce{A(g) <=> B(g)} at 300 K300\text{ K}. The standard Gibbs free energy change is ΔG∘=−300R J mol−1\Delta G^\circ = -300 R\text{ J mol}^{-1} and the standard entropy change is ΔS∘=−30R J K−1 mol−1\Delta S^\circ = -30 R\text{ J K}^{-1}\text{ mol}^{-1}. The temperature coefficient (Q10Q_{10}) for the forward reaction between 300 K300\text{ K} and 310 K310\text{ K} is given by ln⁡(Q10,f)=1.5\ln(Q_{10, f}) = 1.5. Assuming ΔH∘\Delta H^\circ and ΔS∘\Delta S^\circ are independent of temperature, what is the value of ln⁡(Q10,b)\ln(Q_{10, b}) for the backward reaction in the same temperature range? (RR is the universal gas constant)

12

An aqueous solution of D-ribose (\ce{C5H10O5}, molar mass =150 g mol−1= 150 \text{ g mol}^{-1}) is prepared at 298 K298 \text{ K}. At this temperature, the molarity of the solution is 2.0 M2.0 \text{ M} and its density is 1.20 g mL−11.20 \text{ g mL}^{-1}. The solution is subsequently heated to 353 K353 \text{ K} in a sealed vessel (assume negligible solvent vaporization). At 353 K353 \text{ K}, the density of the solution decreases to 1.15 g mL−11.15 \text{ g mL}^{-1} due to thermal expansion. Given that the vapor pressure of pure water at 353 K353 \text{ K} is 260 Torr260 \text{ Torr}, determine the vapor pressure of the solution at 353 K353 \text{ K}. Assume ideal behavior for the vapor phase and that Raoult's Law is applicable.

13

Consider the following electrochemical cell at 298 K:

\cePt(s)∣H2(g,1bar)∣HA(aq,C)∣∣Cu2+(aq,1M)∣Cu(s)\ce{Pt(s) | H2(g, 1 bar) | HA(aq, C) || Cu^{2+}(aq, 1 M) | Cu(s)}

where \ceHA\ce{HA} is a weak monoprotic acid with a dissociation constant Ka=1.0×10−5K_a = 1.0 \times 10^{-5}. When the concentration of \ceHA\ce{HA} is C1=0.1 MC_1 = 0.1 \text{ M}, the measured cell potential is E1E_1. When the \ceHA\ce{HA} solution in the anodic compartment is diluted to a concentration C2=7.5×10−6 MC_2 = 7.5 \times 10^{-6} \text{ M}, the cell potential becomes E2E_2. Calculate the magnitude of the change in cell potential, ∣E2−E1∣|E_2 - E_1| in mV.

(Given: 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06 \text{ V}, log⁡2=0.30\log 2 = 0.30, log⁡3=0.48\log 3 = 0.48. Assume activity coefficients are unity.)

14

Consider 1 mol1\text{ mol} of a real gas obeying the Van der Waals equation of state, (P+aV2)(V−b)=RT\left(P + \frac{a}{V^2}\right)(V - b) = RT, undergoing a reversible adiabatic expansion. Recognizing that the internal energy UU of a real gas is a function of both temperature TT and volume VV, which of the following expressions correctly represents the slope of the adiabatic curve, (∂P∂V)S\left(\frac{\partial P}{\partial V}\right)_S, on a P−VP-V indicator diagram? (Assume the molar heat capacity at constant volume, CVC_V, is independent of temperature).

15

Consider the following gas-phase equilibria at 298 K298\text{ K}:

(1) \ceX(g)+2Y(g)⇌2Z(g)Kp1=2×108\ce{X(g) + 2Y(g) \rightleftharpoons 2Z(g)} \quad K_{p1} = 2 \times 10^8 (2) \ceZ(g)⇌W(g)+Y(g)Kp2=5×10−4\ce{Z(g) \rightleftharpoons W(g) + Y(g)} \quad K_{p2} = 5 \times 10^{-4}

A rigid reaction vessel at 298 K298\text{ K} contains the gases with the following instantaneous partial pressures: PX=0.5 barP_X = 0.5\text{ bar}, PY=2.0 barP_Y = 2.0\text{ bar}, PZ=1.0 barP_Z = 1.0\text{ bar}, and PW=5.0 barP_W = 5.0\text{ bar}.

For the overall transformation \ceX(g)⇌2W(g)\ce{X(g) \rightleftharpoons 2W(g)}, determine the standard Gibbs free energy change (ΔG∘\Delta G^\circ) and the actual Gibbs free energy change (ΔG\Delta G) at this instant.

16

Calculate the standard enthalpy of formation (ΔfH∘\Delta_f H^\circ) of the methyl radical, \ceCH3(g)∙\ce{CH3^\bullet_{(g)}}, at 298 K298\text{ K}.

Given the following thermodynamic data at 298 K298\text{ K}: Standard enthalpy of formation of \ceCH4(g)=−75 kJ mol−1\ce{CH4_{(g)}} = -75\text{ kJ mol}^{-1} Enthalpy of sublimation of \ceC(s,graphite)=717 kJ mol−1\ce{C_{(s, graphite)}} = 717\text{ kJ mol}^{-1} Bond dissociation enthalpy of \ceH2(g)=436 kJ mol−1\ce{H2_{(g)}} = 436\text{ kJ mol}^{-1} First bond dissociation enthalpy of \ceCH4(g)\ce{CH4_{(g)}} (\ceCH4(g)−>CH3(g)∙+H(g)∙\ce{CH4_{(g)} -> CH3^\bullet_{(g)} + H^\bullet_{(g)}}) =439 kJ mol−1= 439\text{ kJ mol}^{-1}

17

An electrochemical cell is constructed at 298 K:

\ce{Pt(s) | I^- (0.1 M) | I_2(s) || Fe^{2+} (0.1 M), Fe(OH)_3(s) | Pt(s)}

The right half-cell is buffered at pH=3.0\text{pH} = 3.0.

Given: E\ceFe3+/Fe2+∘=0.77 VE^\circ_{\ce{Fe^{3+}/Fe^{2+}}} = 0.77\text{ V} E\ceI2/I−∘=0.53 VE^\circ_{\ce{I_2/I^-}} = 0.53\text{ V} Ksp(\ceFe(OH)3)=10−38K_{sp}(\ce{Fe(OH)_3}) = 10^{-38} 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06\text{ V} 1 F=96500 C/mol1\text{ F} = 96500\text{ C/mol}

Calculate the cell potential (EcellE_{cell}) and the Gibbs free energy change (ΔG\Delta G) for the cell reaction as written: \ce{2 Fe^{3+}(aq) + 2 I^-(aq) -> 2 Fe^{2+}(aq) + I_2(s)}

18

Consider the oxidation of the triiodide ion (\ce{I_3^-}) by permanganate (\ce{MnO_4^-}) in a basic medium at 298 K, producing iodate (\ce{IO_3^-}) and solid manganese dioxide (\ce{MnO_2(s)}).

The standard reduction potentials at 298 K are: E\ceMnO4−/\ceMnO2,\ceOH−∘=+0.600 VE^\circ_{\ce{MnO_4^-}/\ce{MnO_2}, \ce{OH^-}} = +0.600 \text{ V} E\ceIO3−/\ceI3−,\ceOH−∘=+0.615 VE^\circ_{\ce{IO_3^-}/\ce{I_3^-}, \ce{OH^-}} = +0.615 \text{ V}

An electrochemical cell is constructed using these half-reactions. All soluble species except \ce{OH^-} are maintained at a concentration of 1.0 M.

Calculate the Gibbs Free Energy change (ΔG\Delta G) for the cell reaction, scaled to exactly one mole of \ce{I_3^-}, when the pH of the solution is maintained at 10.0.

(Given: 2.303RTF=0.060 V\frac{2.303 RT}{F} = 0.060 \text{ V} at 298 K, F=96500 C mol−1F = 96500 \text{ C mol}^{-1})

19

One mole of a real gas, obeying the van der Waals equation of state, undergoes an isothermal reversible expansion from an initial volume V1V_1 to a final volume V2V_2 at a constant temperature TT. Which of the following expressions correctly represents the heat absorbed (qq) by the gas during this process? (Given: aa and bb are van der Waals constants, and RR is the universal gas constant).

20

Consider the following electrochemical cell operating reversibly at 300 K300\text{ K} and 1 bar1\text{ bar}:

\ce{Zn(s) | Zn^{2+}(aq, 1 M) || H+(aq, 1 M) | H2(g, 1 bar) | Pt(s)}

The standard EMF of the cell at 300 K300\text{ K} is 0.76 V0.76\text{ V}, and its temperature coefficient is (∂E∘∂T)P=−5.0×10−4 V K−1\left(\frac{\partial E^\circ}{\partial T}\right)_P = -5.0 \times 10^{-4}\text{ V K}^{-1}. Assuming the gases behave ideally, calculate the total reversible work (wrevw_{rev}) and the standard internal energy change (ΔU∘\Delta U^\circ) for the consumption of 1 mole1\text{ mole} of \ce{Zn(s)}.

(Given: F=96500 C mol−1F = 96500\text{ C mol}^{-1}, R=8.3 J K−1 mol−1R = 8.3\text{ J K}^{-1}\text{ mol}^{-1})

21

A gaseous reaction \ce{A(g) -> 2B(g)} follows zero-order kinetics. When the reaction is carried out in a rigid 1.0 L1.0 \text{ L} flask at 300 K300 \text{ K}, the total pressure increases at a constant rate of 0.2463 atm min−10.2463 \text{ atm min}^{-1}.

In a separate experiment, 1.0 mole1.0 \text{ mole} of pure \ce{A(g)} is placed in a cylinder fitted with a frictionless piston at 300 K300 \text{ K}. The initial volume is 10.0 L10.0 \text{ L}. The gas undergoes a reversible isothermal expansion at 300 K300 \text{ K}, during which the volume of the cylinder increases at a constant rate of 0.5 L min−10.5 \text{ L min}^{-1}.

Assuming ideal gas behavior, calculate the magnitude of the work done by the gas (in Joules) during the first 20 minutes20 \text{ minutes} of the expansion.

(Given: R=0.0821 L atm K−1 mol−1=8.314 J K−1 mol−1R = 0.0821 \text{ L atm K}^{-1} \text{ mol}^{-1} = 8.314 \text{ J K}^{-1} \text{ mol}^{-1}, ln⁡2=0.693\ln 2 = 0.693)

22

Initially, 1.0 mol1.0 \text{ mol} of \ceN2O4(g)\ce{N2O4(g)} is placed in a cylinder fitted with a frictionless piston maintained at a constant pressure of 1.0 atm1.0 \text{ atm} and a constant temperature TT. At equilibrium, the degree of dissociation of \ceN2O4(g)\ce{N2O4(g)} into \ceNO2(g)\ce{NO2(g)} is 0.50.5.

Subsequently, 7.8 mol7.8 \text{ mol} of an ideal inert gas (He) is reversibly and isothermally added to the cylinder, maintaining the constant pressure of 1.0 atm1.0 \text{ atm}.

What is the magnitude of the expansion work done by the system during the addition of the inert gas? (Assume ideal gas behavior for all gases)

23

Consider a hydrogen-oxygen fuel cell operating reversibly and isothermally at 298 K298 \text{ K} and 1 bar1 \text{ bar}. The overall cell reaction is: \ceH2(g)+1/2O2(g)−>H2O(l)\ce{H2(g) + 1/2O2(g) -> H2O(l)} Given the standard thermodynamic data at 298 K298 \text{ K}: ΔfH∘(\ceH2O,l)=−285.8 kJ mol−1\Delta_f H^\circ(\ce{H2O, l}) = -285.8 \text{ kJ mol}^{-1} ΔfS∘(\ceH2O,l)=−163.3 J K−1 mol−1\Delta_f S^\circ(\ce{H2O, l}) = -163.3 \text{ J K}^{-1} \text{ mol}^{-1} R=8.314 J K−1 mol−1R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1} Assume ideal gas behavior and negligible volume for liquid water. Which of the following represents the correct values of heat exchanged (qq) and the change in internal energy (ΔU\Delta U) for the consumption of 1 mole1 \text{ mole} of \ceH2(g)\ce{H2(g)}?

24

For a transition metal MM which forms a 3d83d^8 M2+M^{2+} ion, the following thermodynamic parameters are given at 300 K300 \text{ K}:

∙\bullet Enthalpy of atomization, ΔHat=430 kJ mol−1\Delta H_{at} = 430 \text{ kJ mol}^{-1} ∙\bullet Sum of first and second ionization enthalpies, IE1+IE2=2490 kJ mol−1IE_1 + IE_2 = 2490 \text{ kJ mol}^{-1} ∙\bullet Isotropic (spherical) hydration enthalpy of M2+(g)M^{2+}(g), ΔHhyd,iso=−1980 kJ mol−1\Delta H_{hyd, iso} = -1980 \text{ kJ mol}^{-1} ∙\bullet Crystal field splitting energy (Δo\Delta_o) for the octahedral aquo complex [M(H2O)6]2+[M(H_2O)_6]^{2+} is 100 kJ mol−1100 \text{ kJ mol}^{-1} ∙\bullet Standard entropy change for the half-reaction M(s)→M2+(aq)+2e−M(s) \rightarrow M^{2+}(aq) + 2e^-, ΔS∘=+100 J K−1 mol−1\Delta S^\circ = +100 \text{ J K}^{-1} \text{ mol}^{-1} ∙\bullet Absolute standard Gibbs free energy of oxidation for H2(g)→2H+(aq)+2e−H_2(g) \rightarrow 2H^+(aq) + 2e^- is +838.25 kJ mol−1+838.25 \text{ kJ mol}^{-1}

Calculate the standard reduction potential EM2+/M∘E^\circ_{M^{2+}/M} at 300 K300 \text{ K}. (Given: F=96500 C mol−1F = 96500 \text{ C mol}^{-1})

25

Consider the acid-catalyzed esterification of octadecanoic acid with octan-1-ol to form octyl octadecanoate and water. At 298 K298\text{ K}, the standard enthalpy and entropy of the reaction producing liquid water are ΔHrxn∘=−12.0 kJ mol−1\Delta H^\circ_{rxn} = -12.0\text{ kJ mol}^{-1} and ΔSrxn∘=−10.0 J K−1 mol−1\Delta S^\circ_{rxn} = -10.0\text{ J K}^{-1}\text{ mol}^{-1}, respectively.

The standard enthalpy of vaporization of water is ΔHvap∘=42.0 kJ mol−1\Delta H^\circ_{vap} = 42.0\text{ kJ mol}^{-1} and its standard entropy of vaporization is ΔSvap∘=110.0 J K−1 mol−1\Delta S^\circ_{vap} = 110.0\text{ J K}^{-1}\text{ mol}^{-1}.

The reaction is carried out at 400 K400\text{ K} in a continuous flow reactor. Due to the high boiling points of the organic species, they remain entirely in the liquid phase, but water is formed exclusively in the vapor phase. Assuming all standard enthalpies and entropies are independent of temperature, what is the value of ln⁡K\ln K for this specific equilibrium at 400 K400\text{ K}?

(RR is the universal gas constant in J K−1 mol−1\text{J K}^{-1}\text{ mol}^{-1})

26

Consider the homolytic cleavage of the C3−HC_3-H bond in 1,4-pentadiene, \ce{C5H8(g)}, to form the pentadienyl radical, \ce{C5H7^\bullet(g)}, and a hydrogen atom, \ce{H^\bullet(g)}, at 298 K298 \text{ K}. You are given the following thermodynamic data at 298 K298 \text{ K}: Standard enthalpy of formation of 1,4-pentadiene, ΔHf∘(\ceC5H8,g)=106 kJ mol−1\Delta H_f^\circ(\ce{C5H8}, g) = 106 \text{ kJ mol}^{-1} Standard enthalpy of formation of a hydrogen atom, ΔHf∘(\ceH∙,g)=218 kJ mol−1\Delta H_f^\circ(\ce{H^\bullet}, g) = 218 \text{ kJ mol}^{-1} Standard localized C(sp3)−HC(sp^3)-H bond dissociation enthalpy =415 kJ mol−1= 415 \text{ kJ mol}^{-1} Resonance energy of the pentadienyl radical =82 kJ mol−1= 82 \text{ kJ mol}^{-1} (Assume the resonance energy of 1,4-pentadiene is negligible). Calculate the standard enthalpy of formation of the pentadienyl radical, ΔHf∘(\ceC5H7∙,g)\Delta H_f^\circ(\ce{C5H7^\bullet}, g).

27

Consider the SN1S_N1 solvolysis of the optically active alkyl halide (2S,3S)-2-chloro-3-methylpentane in \ce{H2O} at 298 K. The reaction proceeds via an initial carbocation C1+C_1^+ which undergoes a rapid 1,2-shift to form a more thermodynamically stable carbocation C2+C_2^+, ultimately yielding the major product PP. The global enthalpy path shifts due to the superior hyperconjugative stabilization of C2+C_2^+.

Let n1n_1 and n2n_2 be the number of hyperconjugable α\alpha-hydrogens in C1+C_1^+ and C2+C_2^+, respectively. Identify the major product PP, its optical activity, and the difference in hyperconjugable hydrogens (Δn=n2−n1\Delta n = n_2 - n_1) that provides the thermodynamic driving force (ΔHrearr<0\Delta H_{\text{rearr}} < 0) for the shift.

28

To investigate the thermodynamic stability of high oxidation state fluorides, a student models the formation of gaseous sulfur hexafluoride, \ceSF6(g)\ce{SF6(g)}, using a hypothetical gas-phase ionic Born-Haber cycle. The student assumes the formation of isolated \ceS6+(g)\ce{S^{6+}(g)} and \ceF−(g)\ce{F^{-}(g)} ions, which then condense to form the covalent \ceSF6(g)\ce{SF6(g)} molecule. Given the following thermodynamic data at 298 K: Standard enthalpy of formation of \ceSF6(g)\ce{SF6(g)}, ΔfH∘=−1209 kJ/mol\Delta_f H^\circ = -1209 \text{ kJ/mol} Enthalpy of atomization of \ceS(s)\ce{S(s)}, ΔatomH∘=277 kJ/mol\Delta_{atom} H^\circ = 277 \text{ kJ/mol} Bond dissociation enthalpy of \ceF2(g)\ce{F2(g)}, ΔdissH∘=159 kJ/mol\Delta_{diss} H^\circ = 159 \text{ kJ/mol} Sum of the first six ionization enthalpies of \ceS(g)\ce{S(g)}, ∑i=16IEi=27700 kJ/mol\sum_{i=1}^6 IE_i = 27700 \text{ kJ/mol} Electron gain enthalpy of \ceF(g)\ce{F(g)}, ΔegH∘=−328 kJ/mol\Delta_{eg} H^\circ = -328 \text{ kJ/mol} Calculate the hypothetical 'gas-phase condensation enthalpy' (ΔcondH∘\Delta_{cond} H^\circ) in kJ/mol—the energy released when one mole of \ceS6+(g)\ce{S^{6+}(g)} and six moles of \ceF−(g)\ce{F^{-}(g)} combine to form one mole of \ceSF6(g)\ce{SF6(g)}.

29

Calculate the boiling point elevation (ΔTb\Delta T_b) of a 2.00 molal2.00\text{ molal} aqueous solution of a non-volatile, non-electrolyte solute.

Given data: Standard enthalpy of vaporization of water at 298 K298\text{ K}, ΔHvap∘(298 K)=44.0 kJ mol−1\Delta H_{vap}^\circ(298\text{ K}) = 44.0\text{ kJ mol}^{-1} Molar heat capacities at constant pressure: Cp,m(\ceH2O,l)=75.0 J K−1mol−1C_{p,m}(\ce{H2O}, l) = 75.0\text{ J K}^{-1}\text{mol}^{-1}, Cp,m(\ceH2O,g)=35.0 J K−1mol−1C_{p,m}(\ce{H2O}, g) = 35.0\text{ J K}^{-1}\text{mol}^{-1} Boiling point of pure water, Tb∘=373 KT_b^\circ = 373\text{ K} Universal gas constant, R=8.314 J K−1mol−1R = 8.314\text{ J K}^{-1}\text{mol}^{-1} Molar mass of water, M=18.0 g mol−1M = 18.0\text{ g mol}^{-1}

Assume Cp,mC_{p,m} values are independent of temperature.

30

One mole of liquid \ce{X2} at 500 K500\text{ K} and 1 atm1\text{ atm} is placed in an insulated, constant-pressure chamber. A catalyst is introduced, triggering the endothermic decomposition and phase change: \ceX2(l)−>2X(g)\ce{X2(l) -> 2X(g)} The reaction proceeds via a highly reactive steady-state intermediate \ce{X^*(g)}, ensuring the process is strictly irreversible. The reaction goes to completion. Given the following thermodynamic parameters at 500 K500\text{ K}: ΔHrxn∘=10.0 kJ mol−1\Delta H^\circ_{\text{rxn}} = 10.0\text{ kJ mol}^{-1} Sm∘(\ceX2,l)=100 J K−1mol−1S^\circ_{m}(\ce{X2}, l) = 100\text{ J K}^{-1}\text{mol}^{-1} Sm∘(\ceX,g)=100 J K−1mol−1S^\circ_{m}(\ce{X}, g) = 100\text{ J K}^{-1}\text{mol}^{-1} Cp,m(\ceX,g)=25 J K−1mol−1C_{p,m}(\ce{X}, g) = 25\text{ J K}^{-1}\text{mol}^{-1} (assumed independent of temperature) Assume the heat capacity of the chamber is negligible. What is the total entropy change of the universe (ΔSuniv\Delta S_{\text{univ}}) for this process? (Take ln⁡(0.6)=−0.51\ln(0.6) = -0.51)

31

Consider two independent systems at 298 K298 \text{ K}:

\textbf{System I:} xx moles of an ideal monoatomic gas undergoes adiabatic free expansion from a volume VV to 10V10V. The entropy change of the universe for this process is ΔSI\Delta S_I.

\textbf{System II:} A galvanic cell is constructed as follows: \cePt∣H2(g,1bar)∣HA(aq,0.1M)∣∣HCl(aq,0.1M)∣H2(g,1bar)∣Pt\ce{Pt | H2 (g, 1 bar) | HA (aq, 0.1 M) || HCl (aq, 0.1 M) | H2 (g, 1 bar) | Pt} where \ceHA\ce{HA} is a weak monoprotic acid with Ka=10−5K_a = 10^{-5} at 298 K298 \text{ K}. The standard enthalpy of dissociation of \ceHA\ce{HA} is ΔHdiss∘=17.115 kJ mol−1\Delta H^\circ_{diss} = 17.115 \text{ kJ mol}^{-1}. The entropy change of the cell reaction (ΔSrxn=nF(∂E∂T)P\Delta S_{rxn} = nF \left(\frac{\partial E}{\partial T}\right)_P) per mole of \ceH2\ce{H2} oxidized is ΔSII\Delta S_{II}.

Given that ΔSI=ΔSII\Delta S_I = \Delta S_{II}, and assuming ideal behavior for all solutions and gases, what is the value of xx and the initial cell potential EcellE_{cell} at 298 K298 \text{ K}?

(Given: 2.303RTF=0.059 V\frac{2.303 RT}{F} = 0.059 \text{ V} and 2.303RT=5.705 kJ mol−12.303 RT = 5.705 \text{ kJ mol}^{-1} at 298 K298 \text{ K})

32

An equilibrium mixture of \ceF2(g)+Cl2(g)<=>2ClF(g)\ce{F2(g) + Cl2(g) <=> 2ClF(g)} (ΔH∘=−108 kJ/mol\Delta H^\circ = -108 \text{ kJ/mol}) is contained in a thermally insulated cylinder at temperature T1T_1, fitted with a locked, frictionless piston. 2.0 moles2.0 \text{ moles} of ideal Argon gas (\ceAr\ce{Ar}) are injected into the cylinder. Immediately after, the piston is unlocked, allowing the gas mixture to undergo adiabatic expansion against a constant external pressure until mechanical equilibrium is reached at a new temperature T2T_2. Let ΔT=T2−T1\Delta T = T_2 - T_1 and Δn\ceClF\Delta n_{\ce{ClF}} be the net change in the number of moles of \ceClF\ce{ClF} from the initial to the final equilibrium state. Which of the following correctly represents ΔT\Delta T and Δn\ceClF\Delta n_{\ce{ClF}}?

33

A non-linear polyatomic ideal gas \ce{X} undergoes a unimolecular isomerization \ce{X(g) -> Y(g)} following the Lindemann-Hinshelwood mechanism. At 300 K300\text{ K}, the reaction operates strictly at the low-pressure limit. The gas is initially confined in a vessel of volume V0V_0 and is essentially pure \ce{X}. It then undergoes an adiabatic free expansion against zero external pressure until its volume becomes 8V08V_0.

Let keffk_{eff} be the effective first-order rate constant defined by Rate=keff[\ceX]\text{Rate} = k_{eff}[\ce{X}]. Given that the activation energy for the bimolecular energization step is Ea=300Rln⁡(4)E_a = 300 R \ln(4) and assuming the Arrhenius pre-exponential factor is independent of temperature, what is the ratio of the effective first-order rate constant immediately after the expansion to that before the expansion, keff,2keff,1\frac{k_{eff,2}}{k_{eff,1}}?

34

An electrochemical cell is constructed as follows:

\ceM(s)∣M2+(aq,1M)∣∣X−(aq,1M)∣X2(g,V,T)∣Pt(s)\ce{M(s) | M^{2+}(aq, 1 M) || X^{-}(aq, 1 M) | X_2(g, V, T) | Pt(s)}

The cathodic compartment initially contains 10 moles10 \text{ moles} of a real gas \ceX2\ce{X_2} in a volume of 2.0 L2.0 \text{ L} at 400 K400 \text{ K}. The gas undergoes adiabatic free expansion against a vacuum until its volume becomes 10.0 L10.0 \text{ L}.

Given for \ceX2(g)\ce{X_2(g)}: van der Waals constants: a=6.0 L2 atm mol−2a = 6.0 \text{ L}^2 \text{ atm mol}^{-2}, b=0b = 0. Molar heat capacity at constant volume, Cv,m=3RC_{v,m} = 3 R.

Standard electrode potentials (assumed independent of temperature): E\ceM2+/M∘=−0.76 VE^\circ_{\ce{M^{2+}/M}} = -0.76 \text{ V} E\ceX2/X−∘=+1.36 VE^\circ_{\ce{X_2/X^-}} = +1.36 \text{ V}

Assume the activity of \ceX2(g)\ce{X_2(g)} in the Nernst equation is numerically equal to its pressure in atm. Use R=0.08 L atm K−1 mol−1R = 0.08 \text{ L atm K}^{-1} \text{ mol}^{-1}, 2.303R×300F=0.06 V\frac{2.303 R \times 300}{F} = 0.06 \text{ V}. log⁡102=0.30\log_{10} 2 = 0.30, log⁡103=0.48\log_{10} 3 = 0.48.

Calculate the EMF of the cell after the expansion is complete.

35

The standard enthalpy of formation of gaseous Molybdenum hexachloride, \ceMoCl6(g)\ce{MoCl6}(g), is −840 kJ mol−1-840 \text{ kJ mol}^{-1} and that of Molybdenum tetrachloride, \ceMoCl4(g)\ce{MoCl4}(g), is −380 kJ mol−1-380 \text{ kJ mol}^{-1} at 298 K298 \text{ K}. The standard enthalpy of atomization of solid Molybdenum, ΔatomH∘(\ceMo,s)\Delta_{atom}H^\circ(\ce{Mo}, s), is 660 kJ mol−1660 \text{ kJ mol}^{-1} and the bond dissociation enthalpy of \ceCl2(g)\ce{Cl2}(g) is 240 kJ mol−1240 \text{ kJ mol}^{-1}.

A student calculates the enthalpy of the decomposition reaction: \ceMoCl6(g)→\ceMoCl4(g)+\ceCl2(g)\ce{MoCl6}(g) \rightarrow \ce{MoCl4}(g) + \ce{Cl2}(g) by erroneously assuming that the average \ceMo−Cl\ce{Mo-Cl} bond enthalpy remains constant across different oxidation states and is equal to its value in \ceMoCl6(g)\ce{MoCl6}(g).

What is the true standard enthalpy of the decomposition reaction, and what is the value calculated by the student, respectively?

36

Compound A, 2-(β\beta-D-glucopyranosyloxy)pyridine, undergoes enzymatic hydrolysis in an aqueous medium at 300 K300\text{ K} to yield D-glucose and 2-hydroxypyridine. The released 2-hydroxypyridine subsequently undergoes complete tautomerization to its more stable keto form, 2-pyridone.\n\nGiven the following thermodynamic data at 300 K300\text{ K}:\n\nStandard enthalpy of combustion (ΔHc∘\Delta H^\circ_c) in kJ/mol\text{kJ/mol}:\nCompound A (s) = −4500-4500\nD-Glucose (s) = −2800-2800\n2-Hydroxypyridine (s, enol form) = −1715-1715\n\nStandard enthalpy of solution (ΔHsol∘\Delta H^\circ_{sol}) in kJ/mol\text{kJ/mol}:\nCompound A (s) = +30+30\nD-Glucose (s) = +12+12\n2-Hydroxypyridine (s, enol form) = +8+8\n\nThermodynamic parameters for the tautomerization \ce2−Hydroxypyridine(aq)<=>2−Pyridone(aq)\ce{2-Hydroxypyridine (aq) <=> 2-Pyridone (aq)}:\nΔGtaut∘=−25.0 kJ/mol\Delta G^\circ_{taut} = -25.0\text{ kJ/mol}\nΔStaut∘=−30.0 J K−1mol−1\Delta S^\circ_{taut} = -30.0\text{ J K}^{-1}\text{mol}^{-1}\n\nCalculate the standard observed enthalpy of the overall reaction (ΔHobs∘\Delta H^\circ_{obs}) for the hydrolysis of Compound A (aq) yielding D-glucose (aq) and 2-pyridone (aq) at 300 K300\text{ K}.

37

Consider the standard Gibbs free energy changes (ΔG∘\Delta G^\circ) for the following processes at 298 K:

For a transition metal MM: Atomization: M(s)→M(g)M(s) \rightarrow M(g), ΔG∘=330 kJ mol−1\Delta G^\circ = 330 \text{ kJ mol}^{-1} Ionization: M(g)→M2+(g)+2e−M(g) \rightarrow M^{2+}(g) + 2e^-, ΔG∘=2700 kJ mol−1\Delta G^\circ = 2700 \text{ kJ mol}^{-1} Hydration: M2+(g)→M2+(aq)M^{2+}(g) \rightarrow M^{2+}(aq), ΔG∘=−1998.8 kJ mol−1\Delta G^\circ = -1998.8 \text{ kJ mol}^{-1}

For a transition metal NN: Atomization: N(s)→N(g)N(s) \rightarrow N(g), ΔG∘=130 kJ mol−1\Delta G^\circ = 130 \text{ kJ mol}^{-1} Ionization: N(g)→N2+(g)+2e−N(g) \rightarrow N^{2+}(g) + 2e^-, ΔG∘=2640 kJ mol−1\Delta G^\circ = 2640 \text{ kJ mol}^{-1} Hydration: N2+(g)→N2+(aq)N^{2+}(g) \rightarrow N^{2+}(aq), ΔG∘=−1950 kJ mol−1\Delta G^\circ = -1950 \text{ kJ mol}^{-1}

The absolute standard Gibbs free energy change for the oxidation half-reaction H2(g)→2H+(aq)+2e−H_2(g) \rightarrow 2H^+(aq) + 2e^- is 965.6 kJ mol−1965.6 \text{ kJ mol}^{-1}.

An aqueous solution containing 1.0 M1.0 \text{ M} of M2+M^{2+} and 1.0 M1.0 \text{ M} of N2+N^{2+} at pH = 0 is electrolyzed using inert electrodes at 298 K and 1 bar pressure. The overpotential for H2H_2 evolution at the cathode is 0.40 V0.40 \text{ V}. Given F=96500 C mol−1F = 96500 \text{ C mol}^{-1}.

What are the standard reduction potentials EM2+/M∘E^\circ_{M^{2+}/M} and EN2+/N∘E^\circ_{N^{2+}/N} respectively, and which species is discharged first at the cathode?

38

A closed reaction vessel at 298 K298 \text{ K} contains a standard acidic aqueous solution ([\ceH+]=1.0 M[\ce{H^+}] = 1.0 \text{ M}). To this, 1.0 mole1.0 \text{ mole} of \ceKMnO4\ce{KMnO4} and 4.0 moles4.0 \text{ moles} of \ceMnSO4\ce{MnSO4} are added. The system is allowed to reach complete thermodynamic equilibrium.

Given the standard reduction potentials at 298 K298 \text{ K}: E∘(\ceMnO4−/Mn2+)=+1.51 VE^\circ(\ce{MnO4^- / Mn^{2+}}) = +1.51 \text{ V} E∘(\ceMnO2/Mn2+)=+1.23 VE^\circ(\ce{MnO2 / Mn^{2+}}) = +1.23 \text{ V} E∘(\ceMn3+/Mn2+)=+1.51 VE^\circ(\ce{Mn^{3+} / Mn^{2+}}) = +1.51 \text{ V}

Calculate the total standard Gibbs free energy change (ΔGtotal∘\Delta G^\circ_{total}) for the complete conversion of the given amounts of reactants to their most thermodynamically stable products. (Assume ideal behavior, standard states for all species except the initial stoichiometric amounts provided, and F=96500 C mol−1F = 96500 \text{ C mol}^{-1})

39

Consider the gas-phase heterolytic cleavage of 2-chloro-3-methylbutane (\ceC5H11Cl\ce{C5H11Cl}) to form the thermodynamically most stable rearranged carbocation intermediate (R′+R'^+) and a chloride ion (\ceCl−\ce{Cl^-}) at 298 K.

Given the following thermodynamic parameters: ∙\bullet Standard enthalpy of formation of \ceC5H11Cl(g)\ce{C5H11Cl} (g), ΔHf∘=−140 kJ/mol\Delta H_f^\circ = -140 \text{ kJ/mol} ∙\bullet Standard enthalpy of formation of \ceCl−(g)\ce{Cl^-} (g), ΔHf∘=−230 kJ/mol\Delta H_f^\circ = -230 \text{ kJ/mol} ∙\bullet The theoretical standard enthalpy of formation of the localized (un-hyperconjugated) 3∘3^\circ carbocation R′+R'^+ is +880 kJ/mol+880 \text{ kJ/mol}. ∙\bullet The hyperconjugative stabilization energy is 12 kJ/mol12 \text{ kJ/mol} per α\alpha-C-H bond.

Calculate the actual enthalpy of reaction (ΔHrxn∘\Delta H_{rxn}^\circ) for this heterolytic cleavage, accounting for the hyperconjugative stabilization of the final rearranged carbocation.

40

Calculate the standard enthalpy of formation (ΔfH∘\Delta_f H^\circ) of liquid tetrachloromethane, \ceCCl4(l)\ce{CCl4(l)}, at 298 K298\text{ K} and 1 bar1\text{ bar}, given the following thermodynamic data:

Enthalpy of sublimation of \ceC(graphite)=715 kJ mol−1\ce{C(graphite)} = 715\text{ kJ mol}^{-1} Enthalpy of vaporization of \ceCCl4(l)=30 kJ mol−1\ce{CCl4(l)} = 30\text{ kJ mol}^{-1} Bond dissociation enthalpy of \ceCl−Cl(g)=242 kJ mol−1\ce{Cl-Cl(g)} = 242\text{ kJ mol}^{-1} Average bond enthalpy of \ceC−Cl(g)=328 kJ mol−1\ce{C-Cl(g)} = 328\text{ kJ mol}^{-1}

41

Consider the thermodynamic parameters governing the standard reduction potentials (EM2+/M∘E^\circ_{M^{2+}/M}) of the 3d transition metal series at 298 K298\text{ K}. The Born-Haber cycle for the half-cell reaction M2+(aq)+2e−→M(s)M^{2+}(aq) + 2e^- \rightarrow M(s) involves the enthalpy of atomization (ΔaH∘\Delta_{a}H^\circ), ionization enthalpies (IE1+IE2IE_1 + IE_2), and hydration enthalpy (ΔhydH∘\Delta_{hyd}H^\circ). Which of the following statements is \textbf{INCORRECT}?

42

Consider the reactions of benzoic acid (\cePhCOOH\ce{PhCOOH}) with an excess of two different organometallic reagents:

\textbf{Reaction I:} \cePhCOOH\ce{PhCOOH} is treated with excess \ceCH3MgBr\ce{CH3MgBr} in anhydrous THF at 298 K, followed by acidic aqueous workup. The major organic product isolated is A\mathbf{A}.

\textbf{Reaction II:} \cePhCOOH\ce{PhCOOH} is treated with excess \ceCH3Li\ce{CH3Li} in anhydrous THF at 298 K, followed by acidic aqueous workup. The major organic product isolated is B\mathbf{B}.

Given that the Pauling electronegativities are Li=0.98\text{Li} = 0.98 and Mg=1.31\text{Mg} = 1.31, which of the following correctly identifies A\mathbf{A} and B\mathbf{B}?

43

Consider the formation of liquid carbon tetrachloride from its constituent elements in their standard states at 300 K300\text{ K} in a closed, rigid container:

\ceC(graphite)+2Cl2(g)−>CCl4(l)\ce{C(graphite) + 2Cl2(g) -> CCl4(l)}

You are provided with the following thermodynamic data at 300 K300\text{ K}: ∙\bullet Enthalpy of sublimation of \ceC(graphite)=715.0 kJ mol−1\ce{C(graphite)} = 715.0\text{ kJ mol}^{-1} ∙\bullet Enthalpy of vaporization of \ceCCl4(l)=30.0 kJ mol−1\ce{CCl4(l)} = 30.0\text{ kJ mol}^{-1} ∙\bullet Bond dissociation enthalpy of \ceCl−Cl(g)=242.0 kJ mol−1\ce{Cl-Cl(g)} = 242.0\text{ kJ mol}^{-1} ∙\bullet Mean bond enthalpy of \ceC−Cl(g)=328.0 kJ mol−1\ce{C-Cl(g)} = 328.0\text{ kJ mol}^{-1} ∙\bullet Universal gas constant R=8.3 J K−1 mol−1R = 8.3\text{ J K}^{-1}\text{ mol}^{-1}

Calculate the standard change in internal energy (ΔU∘\Delta U^\circ) for the formation of 1 mole1\text{ mole} of \ceCCl4(l)\ce{CCl4(l)} at 300 K300\text{ K}.

44

Consider the following sequential reactions for the synthesis of a solid material \ceD(s)\ce{D(s)} from gaseous precursors \ceA(g)\ce{A(g)} and \ceB(g)\ce{B(g)}:

Step 1: \ceA(g)+B(g)⇌C(g)\ce{A(g) + B(g) \rightleftharpoons C(g)} Step 2: \ceC(g)⇌D(s)\ce{C(g) \rightleftharpoons D(s)}

The standard thermodynamic parameters (ΔHf∘\Delta H_f^\circ in kJ mol−1\text{kJ mol}^{-1}, S∘S^\circ in J K−1 mol−1\text{J K}^{-1} \text{ mol}^{-1}) at 298 K298 \text{ K} are given as follows: \ceA(g)\ce{A(g)} (5050, 200200); \ceB(g)\ce{B(g)} (5050, 200200); \ceC(g)\ce{C(g)} (−40-40, 200200); \ceD(s)\ce{D(s)} (−140-140, 100100).

Assuming these values are independent of temperature, identify the crossover temperature (TeqT_{eq}) for the overall net reaction, and the value of the net standard Gibbs free energy change (ΔGnet∘\Delta G^\circ_{net}) at 750 K750 \text{ K}.

45

Consider the following redox reaction at 298 K298 \text{ K}:

\ceAg+(aq)+Fe2+(aq)⇌Ag(s)+Fe3+(aq)\ce{Ag+(aq) + Fe^{2+}(aq) \rightleftharpoons Ag(s) + Fe^{3+}(aq)}

Given standard reduction potentials: E\ceAg+/Ag∘=+0.80 VE^\circ_{\ce{Ag+/Ag}} = +0.80 \text{ V} and E\ceFe3+/Fe2+∘=+0.77 VE^\circ_{\ce{Fe^{3+}/Fe^{2+}}} = +0.77 \text{ V}. The initial concentrations of the aqueous species are [\ceAg+]=10−2 M[\ce{Ag+}] = 10^{-2} \text{ M}, [\ceFe2+]=10−3 M[\ce{Fe^{2+}}] = 10^{-3} \text{ M}, and [\ceFe3+]=10−1 M[\ce{Fe^{3+}}] = 10^{-1} \text{ M}.

Assuming 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06 \text{ V} and F=96500 C/molF = 96500 \text{ C/mol}, determine the Gibbs free energy change (ΔG\Delta G) for the reaction under these conditions and predict its spontaneity in the forward direction.

46

The chelate effect is classically responsible for the enhanced stability of complexes containing polydentate ligands. Consider the ligand substitution reaction of a d10d^{10} Cadmium(II) complex at 300 K300 \text{ K}:

\ce[Cd(NH3)4]2+(aq)+2en(aq)<=>[Cd(en)2]2+(aq)+4NH3(aq)\ce{[Cd(NH3)4]^{2+}(aq) + 2en(aq) <=> [Cd(en)2]^{2+}(aq) + 4NH3(aq)}

The thermodynamic parameters for the formation of these complexes from \ce[Cd(H2O)6]2+\ce{[Cd(H2O)6]^{2+}} at 300 K300 \text{ K} are provided below: Overall formation constant (log⁡β4\log \beta_4) for \ce[Cd(NH3)4]2+=7.0\ce{[Cd(NH3)4]^{2+}} = 7.0 Overall formation constant (log⁡β2\log \beta_2) for \ce[Cd(en)2]2+=10.5\ce{[Cd(en)2]^{2+}} = 10.5 Standard enthalpy of complexation (ΔHc∘\Delta H^\circ_c) for \ce[Cd(NH3)4]2+=−53.0 kJ mol−1\ce{[Cd(NH3)4]^{2+}} = -53.0 \text{ kJ mol}^{-1} Standard enthalpy of complexation (ΔHc∘\Delta H^\circ_c) for \ce[Cd(en)2]2+=−56.0 kJ mol−1\ce{[Cd(en)2]^{2+}} = -56.0 \text{ kJ mol}^{-1}

Evaluate the standard entropy change (ΔSsub∘\Delta S^\circ_{sub}) for this substitution reaction and identify the dominant thermodynamic driving force. (Given: 2.303RT=5.75 kJ mol−12.303 RT = 5.75 \text{ kJ mol}^{-1} at 300 K300 \text{ K})

47

Consider the gas-phase Diels-Alder cycloaddition: \ce1,3−Butadiene(g)+Ethene(g)−>Cyclohexene(g)\ce{1,3-Butadiene(g) + Ethene(g) -> Cyclohexene(g)} at 298 K298\text{ K}. The standard thermodynamic parameters for the reaction are ΔH∘=−167 kJ mol−1\Delta H^\circ = -167\text{ kJ mol}^{-1} and ΔS∘=−180 J K−1mol−1\Delta S^\circ = -180\text{ J K}^{-1}\text{mol}^{-1}. Despite being thermodynamically favorable, the reaction does not proceed at an observable rate at 298 K298\text{ K}. Experimental kinetic data reveals an anomalously low Arrhenius pre-exponential factor A≈106 M−1s−1A \approx 10^6\text{ M}^{-1}\text{s}^{-1} (compared to a typical collision frequency of ∼1011 M−1s−1\sim 10^{11}\text{ M}^{-1}\text{s}^{-1}). Based on Transition State Theory, which of the following correctly evaluates the standard Gibbs free energy (ΔG298∘\Delta G^\circ_{298}) and identifies the primary kinetic bottleneck?

48

A 1.0 molal1.0\text{ molal} aqueous solution of a binary electrolyte \ce{AB} is prepared at 300 K300\text{ K}. The freezing point of this solution is −3.0∘C-3.0^\circ\text{C}. (Given: KfK_f of water =2.0 K kg mol−1= 2.0\text{ K kg mol}^{-1}, assume the Van't Hoff factor ii is independent of temperature).

For the dissolution of \ce{AB(s)}, the standard enthalpy of solution at infinite dilution is ΔHsol∞=+15.0 kJ mol−1\Delta H_{sol}^{\infty} = +15.0\text{ kJ mol}^{-1}. At 1.0 m1.0\text{ m} concentration, ion-pairing and non-ideal interactions contribute an excess enthalpy term ΔHexcess=+4.5 kJ mol−1\Delta H_{excess} = +4.5\text{ kJ mol}^{-1}, such that the actual enthalpy of solution is ΔHsol=ΔHsol∞+ΔHexcess\Delta H_{sol} = \Delta H_{sol}^{\infty} + \Delta H_{excess}.

The entropy of dissolution for a hypothetical, fully dissociated ideal solution (i=2i=2) is +80 J K−1 mol−1+80\text{ J K}^{-1}\text{ mol}^{-1}. Given that the actual entropy of dissolution scales linearly with the Van't Hoff factor (ii), determine the Gibbs free energy of dissolution (ΔGsol\Delta G_{sol}) for 1 mole1\text{ mole} of \ce{AB} at 300 K300\text{ K}.

49

A solution is prepared by dissolving 12.2 g12.2 \text{ g} of benzoic acid (\ceC6H5COOH\ce{C6H5COOH}) in 200 g200 \text{ g} of benzene (\ceC6H6\ce{C6H6}) at 280 K280 \text{ K}. Pure benzene freezes at 280 K280 \text{ K} and its entropy of fusion at the freezing point is 34.86 J K−1 mol−134.86 \text{ J K}^{-1} \text{ mol}^{-1}. The observed freezing point of the solution is 278.44 K278.44 \text{ K}. Assuming benzoic acid undergoes dimerization in benzene (\ce2C6H5COOH⇌(C6H5COOH)2\ce{2C6H5COOH \rightleftharpoons (C6H5COOH)2}), calculate the equilibrium constant for the dimerization process in terms of molality (KmK_m) at the freezing point.\n\n(Given: Universal gas constant R=8.3 J K−1 mol−1R = 8.3 \text{ J K}^{-1} \text{ mol}^{-1}, Molar mass of \ceC6H6=78 g mol−1\ce{C6H6} = 78 \text{ g mol}^{-1}, Molar mass of \ceC6H5COOH=122 g mol−1\ce{C6H5COOH} = 122 \text{ g mol}^{-1})

50

Consider the standard electrode potential E\ceM2+/M∘E^\circ_{\ce{M^{2+}/M}} for a 3d transition metal \ceM\ce{M} at 298 K298\text{ K}. The thermodynamic parameters for the Born-Haber cycle of the half-reaction \ceM(s)−>M2+(aq)+2e−\ce{M(s) -> M^{2+}(aq) + 2e^-} are given below:

ΔHsublimation∘=280 kJ mol−1\Delta H^\circ_{\text{sublimation}} = 280\text{ kJ mol}^{-1} ΔSsublimation∘=100 J K−1 mol−1\Delta S^\circ_{\text{sublimation}} = 100\text{ J K}^{-1}\text{ mol}^{-1} ΔGionization∘(\ceM(g)−>M2+(g)+2e−)=1800 kJ mol−1\Delta G^\circ_{\text{ionization}} (\ce{M(g) -> M^{2+}(g) + 2e^-}) = 1800\text{ kJ mol}^{-1} ΔHhydration∘(\ceM2+(g))=−1900 kJ mol−1\Delta H^\circ_{\text{hydration}} (\ce{M^{2+}(g)}) = -1900\text{ kJ mol}^{-1} ΔShydration∘(\ceM2+(g))=−260 J K−1 mol−1\Delta S^\circ_{\text{hydration}} (\ce{M^{2+}(g)}) = -260\text{ J K}^{-1}\text{ mol}^{-1}

Given the Faraday constant F=96500 C mol−1F = 96500\text{ C mol}^{-1}, calculate the standard reduction potential E\ceM2+/M∘E^\circ_{\ce{M^{2+}/M}} in Volts. (Assume standard state conditions and ideal behavior).

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