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Question #44228
The Question
A non-linear polyatomic ideal gas \ce{X} undergoes a unimolecular isomerization \ce{X(g) -> Y(g)} following the Lindemann-Hinshelwood mechanism. At , the reaction operates strictly at the low-pressure limit. The gas is initially confined in a vessel of volume and is essentially pure \ce{X}. It then undergoes an adiabatic free expansion against zero external pressure until its volume becomes .
Let be the effective first-order rate constant defined by . Given that the activation energy for the bimolecular energization step is and assuming the Arrhenius pre-exponential factor is independent of temperature, what is the ratio of the effective first-order rate constant immediately after the expansion to that before the expansion, ?
Options
- A.
1/8
- B.
1
- C.
1/32
- D.
1/4
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Adiabatic Free Expansion|Arrhenius Pre-exponential Factor
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of First Law thermodynamics and chemical kinetics.
The primary trap is the 'adiabatic' keyword.
Students often reflexively apply the reversible adiabatic relation to find a new temperature (which would yield for a non-linear polyatomic gas where , leading to the distractors or ).
However, for an adiabatic free expansion, and , so and temperature remains constant.
The secondary trap is assuming that since is constant, the effective rate constant is also invariant (leading to distractor ).
In the Lindemann low-pressure limit, the reaction is effectively second-order, meaning the pseudo-first-order rate constant is directly proportional to the concentration of the gas, which drops by a factor of 8 upon expansion.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Thermodynamics - Class 11 Part 1 |
| Concept | Adiabatic Free Expansion |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |