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Question #44054

Difficulty: 8/10 | 🟢 Free

The Question

The standard Gibbs free energy of dissociation (ΔGdiss∘\Delta G^\circ_{diss}) for acetic acid (\ceCH3COOH\ce{CH3COOH}) and pivalic acid (\ce(CH3)3CCOOH\ce{(CH3)3CCOOH}) are evaluated at 298 K298\text{ K} in two different media: Water (ϵ=78.4\epsilon = 78.4) and the Gas Phase (ϵ=1\epsilon = 1). Let ΔΔGaq∘=ΔGdiss,aq∘(pivalic)−ΔGdiss,aq∘(acetic)\Delta \Delta G^\circ_{aq} = \Delta G^\circ_{diss, aq}(\text{pivalic}) - \Delta G^\circ_{diss, aq}(\text{acetic}) and ΔΔGgas∘=ΔGdiss,gas∘(pivalic)−ΔGdiss,gas∘(acetic)\Delta \Delta G^\circ_{gas} = \Delta G^\circ_{diss, gas}(\text{pivalic}) - \Delta G^\circ_{diss, gas}(\text{acetic}). Which of the following correctly identifies the signs of ΔΔGaq∘\Delta \Delta G^\circ_{aq} and ΔΔGgas∘\Delta \Delta G^\circ_{gas}, and the dominant physical phenomenon dictating the gas-phase thermodynamic trend?

Options

  • A.

    ΔΔGaq∘>0\Delta \Delta G^\circ_{aq} > 0, ΔΔGgas∘<0\Delta \Delta G^\circ_{gas} < 0, Polarizability effect

  • B.

    ΔΔGaq∘>0\Delta \Delta G^\circ_{aq} > 0, ΔΔGgas∘>0\Delta \Delta G^\circ_{gas} > 0, +I Inductive effect

  • C.

    ΔΔGaq∘<0\Delta \Delta G^\circ_{aq} < 0, ΔΔGgas∘<0\Delta \Delta G^\circ_{gas} < 0, +I Inductive effect

  • D.

    ΔΔGaq∘<0\Delta \Delta G^\circ_{aq} < 0, ΔΔGgas∘>0\Delta \Delta G^\circ_{gas} > 0, Steric hindrance

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Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Standard State Conditions|Carboxylic Acid Strength|Inductive Effect (I-Effect)

Why This Question Is Tricky

Common Mistakes

This question tests a critical 'Chemical Exception' where standard +I inductive effect rules fail.

Students often blindly apply the rule that 'alkyl groups are electron-donating (+I) and destabilize anions' to all environments.

However, the +I effect of alkyl groups is largely an artifact of differential solvation in water.

In the gas phase (or strictly non-polar solvents), polarizability dominates over inductive effects.

Larger alkyl groups actually stabilize anions via charge-induced dipole interactions, completely reversing the expected thermodynamic acidity trend.

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Question Information

SubjectChemistry
ChapterThermodynamics - Class 11 Part 1
ConceptStandard State Conditions
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree