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Question #44213
The Question
Consider the oxidation of the triiodide ion (\ce{I_3^-}) by permanganate (\ce{MnO_4^-}) in a basic medium at 298 K, producing iodate (\ce{IO_3^-}) and solid manganese dioxide (\ce{MnO_2(s)}).
The standard reduction potentials at 298 K are:
An electrochemical cell is constructed using these half-reactions. All soluble species except \ce{OH^-} are maintained at a concentration of 1.0 M.
Calculate the Gibbs Free Energy change () for the cell reaction, scaled to exactly one mole of \ce{I_3^-}, when the pH of the solution is maintained at 10.0.
(Given: at 298 K, )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
IUPAC Sign Convention|Fractional Oxidation State Misconception|KMnO₄ Redox pH Dependency
Why This Question Is Tricky
Common Mistakes
The problem tests the 'Fractional Oxidation State Misconception' and 'pH Dependency of Redox Potentials'.
Students often miscalculate the n-factor for polyatomic ions with fractional oxidation states (like \ce{I_3^-}), leading to incorrect electron transfer values.
Furthermore, they frequently apply standard potentials without correcting for the Nernstian shift caused by the pH in basic media.
Here, the reaction is non-spontaneous under standard basic conditions ( V) but becomes spontaneous at pH 10 due to the decreased concentration of the product \ce{OH^-} relative to standard conditions, flipping the sign of .
Failing to scale the reaction to exactly one mole of \ce{I_3^-} or incorrectly balancing with \ce{H^+} leads to the distractors.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Thermodynamics - Class 11 Part 1 |
| Concept | IUPAC Sign Convention |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |