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Question #44234

Difficulty: 8/10 | 🟢 Free

The Question

Consider the gas-phase heterolytic cleavage of 2-chloro-3-methylbutane (\ceC5H11Cl\ce{C5H11Cl}) to form the thermodynamically most stable rearranged carbocation intermediate (R′+R'^+) and a chloride ion (\ceCl−\ce{Cl^-}) at 298 K.

Given the following thermodynamic parameters: ∙\bullet Standard enthalpy of formation of \ceC5H11Cl(g)\ce{C5H11Cl} (g), ΔHf∘=−140 kJ/mol\Delta H_f^\circ = -140 \text{ kJ/mol} ∙\bullet Standard enthalpy of formation of \ceCl−(g)\ce{Cl^-} (g), ΔHf∘=−230 kJ/mol\Delta H_f^\circ = -230 \text{ kJ/mol} ∙\bullet The theoretical standard enthalpy of formation of the localized (un-hyperconjugated) 3∘3^\circ carbocation R′+R'^+ is +880 kJ/mol+880 \text{ kJ/mol}. ∙\bullet The hyperconjugative stabilization energy is 12 kJ/mol12 \text{ kJ/mol} per α\alpha-C-H bond.

Calculate the actual enthalpy of reaction (ΔHrxn∘\Delta H_{rxn}^\circ) for this heterolytic cleavage, accounting for the hyperconjugative stabilization of the final rearranged carbocation.

Options

  • A.

    694 \text{ kJ/mol}

  • B.

    742 \text{ kJ/mol}

  • C.

    790 \text{ kJ/mol}

  • D.

    886 \text{ kJ/mol}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Hess's Law Application|SN1 Carbocation Rearrangement|Hyperconjugation Logic

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of thermodynamic state functions (Hess's Law) and structural organic chemistry (carbocation rearrangement and hyperconjugation).

The 'Hidden Variable' is the enthalpy offset provided by hyperconjugation.

Students often calculate the ΔH\Delta H of the reaction based on theoretical ground states, neglecting that the intermediate's energy is significantly modulated by orbital overlap (σ→p\sigma \rightarrow p delocalization).

Furthermore, the trap penalizes students who fail to perform the 1,2-hydride shift, as calculating the stabilization energy for the initial 2∘2^\circ carbocation (4 α\alpha-H) leads directly to distractor B.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterThermodynamics - Class 11 Part 1
ConceptHess's Law Application
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree