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Question #44219

Difficulty: 8/10 | 🟢 Free

The Question

For a transition metal MM which forms a 3d83d^8 M2+M^{2+} ion, the following thermodynamic parameters are given at 300 K300 \text{ K}:

∙\bullet Enthalpy of atomization, ΔHat=430 kJ mol−1\Delta H_{at} = 430 \text{ kJ mol}^{-1} ∙\bullet Sum of first and second ionization enthalpies, IE1+IE2=2490 kJ mol−1IE_1 + IE_2 = 2490 \text{ kJ mol}^{-1} ∙\bullet Isotropic (spherical) hydration enthalpy of M2+(g)M^{2+}(g), ΔHhyd,iso=−1980 kJ mol−1\Delta H_{hyd, iso} = -1980 \text{ kJ mol}^{-1} ∙\bullet Crystal field splitting energy (Δo\Delta_o) for the octahedral aquo complex [M(H2O)6]2+[M(H_2O)_6]^{2+} is 100 kJ mol−1100 \text{ kJ mol}^{-1} ∙\bullet Standard entropy change for the half-reaction M(s)→M2+(aq)+2e−M(s) \rightarrow M^{2+}(aq) + 2e^-, ΔS∘=+100 J K−1 mol−1\Delta S^\circ = +100 \text{ J K}^{-1} \text{ mol}^{-1} ∙\bullet Absolute standard Gibbs free energy of oxidation for H2(g)→2H+(aq)+2e−H_2(g) \rightarrow 2H^+(aq) + 2e^- is +838.25 kJ mol−1+838.25 \text{ kJ mol}^{-1}

Calculate the standard reduction potential EM2+/M∘E^\circ_{M^{2+}/M} at 300 K300 \text{ K}. (Given: F=96500 C mol−1F = 96500 \text{ C mol}^{-1})

Options

  • A.

    −0.25 V-0.25 \text{ V}

  • B.

    +0.37 V+0.37 \text{ V}

  • C.

    +0.25 V+0.25 \text{ V}

  • D.

    −0.09 V-0.09 \text{ V}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Hess's Law Application|E° (M²⁺/M) Anomalies|Standard State Conditions

Why This Question Is Tricky

Common Mistakes

This problem tests the 'First Law Consistency' within a Born-Haber cycle while integrating Coordination Chemistry.

The primary trap is failing to account for the Crystal Field Stabilization Energy (CFSE) when calculating the true hydration enthalpy from the isotropic value.

A secondary trap involves the thermodynamic definition of standard reduction potentials: students often equate the absolute ΔGox\Delta G_{ox} directly to −nFE∘-nFE^\circ without subtracting the absolute potential of the Standard Hydrogen Electrode (SHE), or they confuse the signs of oxidation and reduction potentials.

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Question Information

SubjectChemistry
ChapterThermodynamics - Class 11 Part 1
ConceptFirst Law Consistency
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree