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Question #44057
The Question
A aqueous solution of a weak monoprotic acid \ce{HA (aq)} freezes at at . The cryoscopic constant of water is . Assume the solution behaves ideally with respect to the solvent (osmotic coefficient ), such that the freezing point depression is strictly proportional to the total molality of all solute particles. However, the acid dissociation equilibrium is non-ideal. If the mean ionic activity coefficient of the ions \ce{H+ (aq)} and \ce{A- (aq)} in this solution is and the activity coefficient of the unionized acid is , what is the true thermodynamic acid dissociation constant () of \ce{HA} at the freezing point?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Standard State Conditions|Raoult’s Law Ideal vs Non-Ideal|Van’t Hoff Factor (i) Application
Why This Question Is Tricky
Common Mistakes
This problem tests the critical distinction between the apparent equilibrium constant () derived from colligative properties and the true thermodynamic equilibrium constant ().
Students frequently fall into the trap of assuming ideal solute behavior () and stopping at .
The 'Hidden Variable' is the mean ionic activity coefficient (), which must be squared to correct the activities of both the cation and anion in the numerator of the equilibrium expression.
Distractors include ignoring the activity coefficient entirely (Option B), failing to square it (Option C), or incorrectly dividing by it (Option D).
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Thermodynamics - Class 11 Part 1 |
| Concept | Standard State Conditions |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |