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Question #44237

Difficulty: 8/10 | 🟢 Free

The Question

Consider the reactions of benzoic acid (\cePhCOOH\ce{PhCOOH}) with an excess of two different organometallic reagents:

\textbf{Reaction I:} \cePhCOOH\ce{PhCOOH} is treated with excess \ceCH3MgBr\ce{CH3MgBr} in anhydrous THF at 298 K, followed by acidic aqueous workup. The major organic product isolated is A\mathbf{A}.

\textbf{Reaction II:} \cePhCOOH\ce{PhCOOH} is treated with excess \ceCH3Li\ce{CH3Li} in anhydrous THF at 298 K, followed by acidic aqueous workup. The major organic product isolated is B\mathbf{B}.

Given that the Pauling electronegativities are Li=0.98\text{Li} = 0.98 and Mg=1.31\text{Mg} = 1.31, which of the following correctly identifies A\mathbf{A} and B\mathbf{B}?

Options

  • A.

    A=\cePh−CO−CH3\mathbf{A} = \ce{Ph-CO-CH3}, B=\cePh−CO−CH3\mathbf{B} = \ce{Ph-CO-CH3}

  • B.

    A=\cePhCOOH\mathbf{A} = \ce{PhCOOH}, B=\cePh−CO−CH3\mathbf{B} = \ce{Ph-CO-CH3}

  • C.

    A=\cePh−C(OH)(CH3)2\mathbf{A} = \ce{Ph-C(OH)(CH3)2}, B=\cePh−CO−CH3\mathbf{B} = \ce{Ph-CO-CH3}

  • D.

    A=\cePhCOOH\mathbf{A} = \ce{PhCOOH}, B=\cePh−C(OH)(CH3)2\mathbf{B} = \ce{Ph-C(OH)(CH3)2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Bond Enthalpy Pitfall|Grignard Reagent Sensitivity

Why This Question Is Tricky

Common Mistakes

The question tests the 'Bond_Enthalpy_Pitfall' and 'Grignard_Reaction_Pathways' by contrasting the reactivity of Grignard and organolithium reagents with carboxylic acids.

Students often assume Grignard reagents will attack the carboxylate, failing to account for the initial protonolysis that forms a highly stable, chelated magnesium carboxylate (an enthalpic sink).

The key hidden variable is the relative electronegativity of Li and Mg; students often mistakenly assume Mg is less electronegative, incorrectly predicting Grignard as the stronger nucleophile.

Furthermore, recognizing the stability of the tetrahedral dilithium intermediate is crucial, as it prevents over-addition to the tertiary alcohol.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterThermodynamics - Class 11 Part 1
ConceptBond Enthalpy Pitfall
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree