Before You Begin
Question #44436
The Question
In the Kiliani-Fischer chain extension, the nucleophilic addition of \ce{CN^-} to the acyclic carbonyl form of a sugar is the rate-determining step. For a heavily branched aldose derivative, 2-C-methyl-D-arabinose, the approach of the cyanide ion along the Bürgi-Dunitz trajectory () is sterically hindered. This causes a significant increase in torsional strain during the rehybridization, mimicking 1,3-diaxial interactions in the transition state. If this steric inhibition reduces the reaction rate constant by a factor of at compared to unbranched D-arabinose, what is the corresponding increase in the activation free energy () for the addition step? (Assume identical pre-exponential factors and at )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Nucleophilic Addition Sterics|Kiliani-Fischer Chain Extension|D-Glucose Anomeric Equilibrium
Why This Question Is Tricky
Common Mistakes
Students often memorize that steric hindrance slows down nucleophilic addition but fail to quantify it thermodynamically.
This question tests the understanding that 'steric inhibition' in carbonyl addition is fundamentally an increase in transition state free energy () due to torsional strain and trajectory constraints (Bürgi-Dunitz angle) during rehybridization.
By linking organic reaction mechanisms with chemical kinetics, it traps students who cannot translate structural constraints into thermodynamic penalties.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Aldehydes, Ketones, and Carboxylic Acids - Class 12 |
| Concept | Nucleophilic Addition Sterics |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |