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Question #44018
The Question
Consider the reaction of 2-ethyl-5-methyl-3-oxohexanenitrile with 1.05 equivalents of Lithium diisopropylamide (LDA) in anhydrous THF at for 1 hour. To this mixture, 1.1 equivalents of methyl iodide (\ce{CH3I}) is added, and the reaction is allowed to warm to room temperature. Identify the major organic product formed.
Options
- A.
2-ethyl-2,5-dimethyl-3-oxohexanenitrile
- B.
2-ethyl-4,5-dimethyl-3-oxohexanenitrile
- C.
2-ethyl-3-methoxy-5-methylhex-2-enenitrile
- D.
4-ethyl-2,5-dimethyl-3-oxohexanenitrile
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Enolate Regioselectivity|Inductive Effect Trends
Why This Question Is Tricky
Common Mistakes
This question tests the boundary conditions of the 'kinetic vs. thermodynamic enolate' heuristic.
Students are taught that bulky bases (LDA) at low temperatures () abstract the least hindered proton to form the kinetic enolate.
However, this 'steric-only' model fails when a strong electron-withdrawing group (like -CN) is present at the more hindered position.
The EWG drastically lowers the pKa of the hindered proton.
This massive thermodynamic driving force lowers the activation energy for deprotonation so much that the sterically hindered proton is abstracted kinetically as well.
The trap is choosing the less hindered C4 alkylation product by blindly applying the LDA/ rule without considering the overriding electronic effect.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Aldehydes, Ketones, and Carboxylic Acids - Class 12 |
| Concept | Enolate Regioselectivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |