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Question #43973

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following substituted benzaldehydes subjected to Cannizzaro reaction conditions using 50% \ceNaOH(aq)50\% \ \ce{NaOH_{(aq)}} at 298 K298\ \text{K}: (I) 4-Nitrobenzaldehyde (II) 3-Nitrobenzaldehyde (III) 2-Nitrobenzaldehyde (IV) 2,6-Dinitrobenzaldehyde

Which of the following represents the correct decreasing order of their initial reaction rates?

Options

  • A.

    I > II > III > IV

  • B.

    IV > III > I > II

  • C.

    IV > I > III > II

  • D.

    I > III > II > IV

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Cannizzaro Mechanism|Inductive Effect Trends|Carboxylic Acid Strength

Why This Question Is Tricky

Common Mistakes

The problem tests the student's ability to distinguish between the electronic favorability of the first step (nucleophilic attack) and the kinetic requirements of the Rate Determining Step (hydride transfer).

Students who rely solely on electronic effects (-I, -M) will predict that ortho-substituted and di-ortho-substituted benzaldehydes react fastest due to increased electrophilicity (Option B).

The hidden variable is the severe steric hindrance in the bimolecular transition state of the hydride transfer.

Excessive ortho-substitution creates a steric bottleneck that destabilizes the transition state, completely reversing the rate trend predicted by simple inductive and mesomeric effects.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAldehydes, Ketones, and Carboxylic Acids - Class 12
ConceptCannizzaro Mechanism
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree