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Question #43965

Difficulty: 8/10 | 🟢 Free

The Question

Consider the intramolecular Aldol condensation of 7,7-dimethyl-6-oxooctanal in the presence of dilute aqueous \ceNaOH\ce{NaOH} at 353 K353\text{ K}. Identify the major organic product formed.

Options

  • A.

    1-(cyclopent-1-en-1-yl)-2,2-dimethylpropan-1-one

  • B.

    2-(tert-butyl)cyclopent-1-ene-1-carbaldehyde

  • C.

    3-(tert-butyl)cyclopent-1-ene-1-carbaldehyde

  • D.

    1-(cyclopent-2-en-1-yl)-2,2-dimethylpropan-1-one

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Aldol Condensation Directionality|Nucleophilic Addition Sterics|Alpha-Hydrogen Acidity

Why This Question Is Tricky

Common Mistakes

This problem tests the Curtin-Hammett principle and the competition between thermodynamic acidity and kinetic nucleophilic attack in an intramolecular Aldol condensation.

Students typically fall into the trap of assuming the most acidic α\alpha-hydrogen (at C2) dictates the reaction, leading them to predict 2-(tert-butyl)cyclopent-1-ene-1-carbaldehyde.

The 'Hidden Variable' is the extreme steric hindrance of the \textit{tert}-butyl group at the C6 electrophilic site, which drastically suppresses the rate of attack.

The reaction is instead funneled through the less stable C5 enolate because its attack on the unhindered C1 aldehyde has a much lower transition state energy.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAldehydes, Ketones, and Carboxylic Acids - Class 12
ConceptAldol Condensation Directionality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree