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Question #43957

Difficulty: 8/10 | 🟢 Free

The Question

An aldopentose, D-lyxose, is subjected to Kiliani-Fischer chain extension to yield a mixture of two epimeric aldonolactones. One of these lactones, YY, is isolated based on the property that its exhaustive reduction yields an optically inactive alditol. Lactone YY is then subjected to two distinct reduction protocols:

\textbf{Protocol I:} Treatment with 1 equivalent of DIBAL-H in toluene at −78∘C-78^\circ\text{C}, followed by mild aqueous acidic workup, yielding compound PP.

\textbf{Protocol II:} Treatment with excess \ceNaBH4\ce{NaBH4} in aqueous ethanol at 298 K298\text{ K}, yielding compound QQ.

Which of the following statements correctly describes the properties of PP and QQ?

Options

  • A.

    PP is an optically active reducing sugar that undergoes mutarotation, whereas QQ is an optically inactive non-reducing sugar.

  • B.

    Both PP and QQ are optically active compounds, but only PP gives a positive Tollens' test.

  • C.

    PP is an optically active reducing sugar, whereas QQ is an optically active non-reducing sugar.

  • D.

    PP is an optically inactive reducing sugar, whereas QQ is a meso compound that does not undergo mutarotation.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Reduction Selectivity (Hydrides)|Kiliani-Fischer Chain Extension|Reducing Sugar Criteria

Why This Question Is Tricky

Common Mistakes

This question tests the chemoselectivity of reducing agents on aldonolactones and the stereochemical symmetry of carbohydrates.

The 'hidden variable' is the kinetic control of DIBAL-H at low temperatures, which halts reduction at the aldehyde (lactol) stage, preserving the reducing sugar properties.

In contrast, NaBH4 thermodynamically reduces the lactone to an alditol.

Furthermore, it tests the ability to visualize the stereocenters of D-lyxose extended to D-galactose, recognizing that its alditol (galactitol) is a meso compound due to a plane of symmetry, a classic stereochemical trap.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAldehydes, Ketones, and Carboxylic Acids - Class 12
ConceptReduction Selectivity (Hydrides)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree