Start Learning Free

Before You Begin

Question #110666

Difficulty: 5/10 | 🟢 Free

The Question

A student attempts the one-pot reductive amination of benzaldehyde (0.10 M0.10\text{ M}) with ethanamine (0.10 M0.10\text{ M}) in an aqueous buffer at pH=4.0\text{pH} = 4.0 and 298 K298\text{ K}. To this mixture, \ceNaBH4\ce{NaBH4} (0.10 M0.10\text{ M}) is immediately added.

The hydrolysis of \ceNaBH4\ce{NaBH4} in acidic media follows second-order kinetics: −d[\ceBH4−]dt=k[\ceH+][\ceBH4−]-\frac{d[\ce{BH4^-}]}{dt} = k[\ce{H^+}][\ce{BH4^-}], where k=1.0×106 L mol−1s−1k = 1.0 \times 10^6\text{ L mol}^{-1}\text{s}^{-1} at 298 K298\text{ K}. The hydrolysis reaction proceeds as follows:

\ce{BH4^- + H^+ + 3H2O -> H3BO3 + 4H2 ^}

Assuming the rate of imine reduction is negligible compared to hydrolysis under these conditions, determine the initial rate of \ceH2\ce{H2} gas evolution and the major organic species isolated after 10 minutes followed by a mild basic workup.

Options

  • A.

    40 mol L−1s−140\text{ mol L}^{-1}\text{s}^{-1} ; NN-benzylideneethanamine

  • B.

    40 mol L−1s−140\text{ mol L}^{-1}\text{s}^{-1} ; NN-ethylbenzylamine

  • C.

    10 mol L−1s−110\text{ mol L}^{-1}\text{s}^{-1} ; NN-benzylideneethanamine

  • D.

    40 L mol−1s−140\text{ L mol}^{-1}\text{s}^{-1} ; NN-benzylideneethanamine

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Schiff Base pH Dependence|Reduction Selectivity (Hydrides)

Why This Question Is Tricky

Examiner Levers

Approximation Bait

Options are extremely close; tests precision vs. early rounding.

Difficulty Boost : +3

Common Mistakes

This problem tests the 'one-pot' reductive amination misconception and integrates a dimensional analysis trap.

Students often memorize that NaBH4 reduces imines but overlook its severe incompatibility with the acidic pH (4-5) required for Schiff base formation.

The problem forces a kinetic calculation to prove that hydride decomposition outpaces reduction, leading to the isolation of the unreduced Schiff base.

It also traps students who forget the 1:4 stoichiometry of BH4- to H2 gas, and those who fail to verify the correct units for the rate of reaction (mol/L/s vs L/mol/s).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAldehydes, Ketones, and Carboxylic Acids - Class 12
ConceptSchiff Base pH Dependence
Difficulty5
Cognitive Load6
Target Solve Time150 sec
AccessFree