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Question #95891

Difficulty: 8/10 | 🟢 Free

The Question

A cylindrical rod of length LL and cross-sectional area AA is oriented along the body diagonal of a cubical room of side aa (so L=3aL = \sqrt{3}a). The rod is fixed between two rigid walls at its ends x=0x=0 and x=Lx=L. The rod has a uniform volume charge density ρe\rho_e and is placed in a uniform magnetic field B⃗=B0k^\vec{B} = B_0 \hat{k}. The rod is initially at a uniform temperature T0T_0. The temperature is then increased such that the change in temperature at a distance xx from the x=0x=0 end is ΔT(x)=ΔT0xL\Delta T(x) = \Delta T_0 \frac{x}{L}. The coefficient of linear thermal expansion varies as α(x)=α0xL\alpha(x) = \alpha_0 \frac{x}{L}. The Young's modulus of the rod varies with temperature as Y(T)=Y01+β(T−T0)Y(T) = \frac{Y_0}{1 + \beta(T - T_0)}. Which of the following statements regarding the rod in its final equilibrium state is INCORRECT?

Options

  • A.

    The net displacement of the cross-section at x=L/2x = L/2 is zero.

  • B.

    The compressive force developed is AY0α0ΔT03(1+12βΔT0)\frac{A Y_0 \alpha_0 \Delta T_0}{3(1 + \frac{1}{2}\beta \Delta T_0)}.

  • C.

    The total free thermal expansion of the rod is 13α0ΔT0L\frac{1}{3} \alpha_0 \Delta T_0 L.

  • D.

    The magnitude of local mechanical strain at x=Lx = L is α0ΔT0(1+βΔT0)3(1+12βΔT0)\frac{\alpha_0 \Delta T_0 (1 + \beta \Delta T_0)}{3(1 + \frac{1}{2}\beta \Delta T_0)}.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Interatomic Force Curve|Dipole Potential Angular Dependence|Electric Field Symmetry

Why This Question Is Tricky

Examiner Levers

Extraneous Data

Provides unnecessary variables (Red Herrings) to test conceptual focus.

Difficulty Boost : +3

Visualization Stress

Requires mental rotation or 3D mapping (Optics/Geometry/Vectors).

Difficulty Boost : +4

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the advanced application of Hooke's Law and thermal expansion in a system with continuously varying properties, deliberately trapping students who rely on lumped-parameter formulas like ΔL=LαΔT\Delta L = L \alpha \Delta T.

The primary trap lies in the assumption of symmetry or zero internal displacement.

Students frequently assume that if a rod is fixed at both ends, its midpoint remains stationary (u(L/2)=0u(L/2) = 0).

However, because the temperature gradient, thermal expansion coefficient, and Young's modulus all vary with position, the local thermal strain and mechanical strain do not cancel out locally, only globally.

The right side of the rod expands significantly more and is mechanically softer, causing the internal cross-sections to shift towards the cooler, stiffer end to maintain equilibrium.

The inclusion of the magnetic field and charge density serves as a conceptual red herring to test confidence in static equilibrium conditions.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Solids - Class 11 Part 2
ConceptInteratomic Force Curve
Difficulty8
Cognitive Load8
Target Solve Time180 sec
AccessFree