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Question #88262

Difficulty: 5/10 | 🟢 Free

The Question

A parallel plate capacitor has plate area A m2A \text{ m}^2 and separation d md \text{ m}. The space between the plates (0≤x≤d0 \le x \le d) is filled with a non-uniform dielectric whose relative permittivity varies as κ(x)=1+xd\kappa(x) = 1 + \frac{x}{d}. A constant potential difference V0 VV_0 \text{ V} is applied across the plates. What is the magnitude of the bound volume charge density (polarization charge density) ρp\rho_p within the dielectric at the plane x=d2x = \frac{d}{2}?

Options

  • A.

    4ϵ0V09d2ln⁡2 C/m3\frac{4 \epsilon_0 V_0}{9 d^2 \ln 2} \text{ C/m}^3

  • B.

    ϵ0V0d2 C/m3\frac{\epsilon_0 V_0}{d^2} \text{ C/m}^3

  • C.

    2ϵ0V03d2 C/m3\frac{2 \epsilon_0 V_0}{3 d^2} \text{ C/m}^3

  • D.

    ϵ0V04d2ln⁡2 C/m3\frac{\epsilon_0 V_0}{4 d^2 \ln 2} \text{ C/m}^3

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Dielectric Polarization Logic|Gauss Law|Integration

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the fundamental distinction between the displacement field DD and the electric field EE in non-uniform dielectrics.

A common trap is assuming the electric field remains uniform (E=V0/dE = V_0/d) despite the gradient dielectric.

If a student makes this error, they calculate P=ϵ0(κ(x)−1)E=ϵ0(x/d)(V0/d)P = \epsilon_0 (\kappa(x)-1) E = \epsilon_0 (x/d) (V_0/d), leading to a constant bound charge density ρp=−∇⋅P=−ϵ0V0/d2\rho_p = -\nabla \cdot P = -\epsilon_0 V_0 / d^2 (Option B).

The correct physical approach recognizes that DD is uniform (driven by free charge on the plates), while EE varies inversely with κ(x)\kappa(x).

Furthermore, finding the true free charge requires integrating the infinitesimal elastances (1/dC1/dC) to find the equivalent capacitance, testing the transition from algebraic formula-memory to fundamental electrostatics.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptDielectric Polarization Logic
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree