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Question #87795

Difficulty: 5/10 | 🟢 Free

The Question

A small carriage of mass MM can move along a frictionless horizontal track aligned with the xx-axis. It is connected to the origin (x=0x=0) by a horizontal spring of spring constant KK, which is relaxed when the carriage is at x=0x=0. A small magnet with magnetic dipole moment μ\mu and moment of inertia II (about the vertical zz-axis) is suspended from the carriage by a vertical torsion fiber of torsional constant CC. The magnet can rotate freely in the horizontal xyxy-plane. The entire system is placed in a static, non-uniform magnetic field given by B⃗=(B0+βx)i^−βyj^\vec{B} = (B_0 + \beta x)\hat{i} - \beta y\hat{j}, where B0B_0 and β\beta are positive constants. Initially, the system is in equilibrium with the dipole moment aligned along the positive xx-axis. If the magnet is given a small angular displacement in the xyxy-plane, what is the angular frequency ω\omega of the resulting torsional oscillations?

Options

  • A.

    C+μB0+μ2β2KI\sqrt{\frac{C + \mu B_0 + \frac{\mu^2 \beta^2}{K}}{I}}

  • B.

    C+μB0I\sqrt{\frac{C + \mu B_0}{I}}

  • C.

    C+μB0−μ2β2KI\sqrt{\frac{C + \mu B_0 - \frac{\mu^2 \beta^2}{K}}{I}}

  • D.

    C+μB0+μ2β22KI\sqrt{\frac{C + \mu B_0 + \frac{\mu^2 \beta^2}{2K}}{I}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Lorentz Force Vector Direction|Magnetic Dipole Moment Orientation|Torsional Oscillations

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the student's ability to couple translational and rotational equilibrium in a non-uniform magnetic field.

The primary trap is calculating the magnetic restoring torque strictly at the origin (x=0x=0), yielding an effective torsional constant of C+μB0C + \mu B_0.

Students often fail to realize that the field gradient β\beta exerts a net translational force (F=∇(μ⃗⋅B⃗)F = \nabla(\vec{\mu} \cdot \vec{B})) that shifts the equilibrium position of the carriage.

Because the magnetic field is stronger at this new shifted position, the magnetic restoring torque is correspondingly higher.

Recognizing that the cross-term in the potential energy expansion is zero ensures the modes are decoupled, allowing the torsional frequency to be evaluated purely at the shifted coordinate.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptLorentz Force Vector Direction
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree