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Question #87054

Difficulty: 5/10 | 🟢 Free

The Question

A p-n junction diode is operating in the reverse breakdown region. To model the transition from Zener to Avalanche breakdown, its dynamic internal resistance is given by rd=dVDdI=λEr_d = \frac{dV_D}{dI} = \frac{\lambda}{E}, where VDV_D is the reverse voltage across the diode, II is the reverse current, E=VDdE = \frac{V_D}{d} is the uniform electric field in the depletion region of width dd, and λ\lambda is a positive constant with units of Ω⋅V⋅m−1\Omega \cdot \text{V} \cdot \text{m}^{-1}. The breakdown onset occurs at VD=VZV_D = V_Z where the macroscopic current I≈0 AI \approx 0 \text{ A}. The diode is connected in series with a resistor RR and a DC power supply of voltage V0V_0 (V0>VZV_0 > V_Z). Which of the following expressions correctly gives the steady-state current II in the circuit?

Options

  • A.

    V0R+λd−(λd)2+2V0Rλd+(RVZ)2R2\frac{V_0 R + \lambda d - \sqrt{(\lambda d)^2 + 2 V_0 R \lambda d + (R V_Z)^2}}{R^2}

  • B.

    V0−VZR\frac{V_0 - V_Z}{R}

  • C.

    V0−VZR+λdVZ\frac{V_0 - V_Z}{R + \frac{\lambda d}{V_Z}}

  • D.

    V0R+λd+(λd)2+2V0Rλd+(RVZ)2R2\frac{V_0 R + \lambda d + \sqrt{(\lambda d)^2 + 2 V_0 R \lambda d + (R V_Z)^2}}{R^2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Internal Resistance Variation|Zener vs Avalanche Breakdown|Depletion Region Dynamics

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

The trap exploits the 'Linearity Bias' where students assume a breakdown diode acts either as an ideal voltage source (VD=VZV_D = V_Z) or has a constant piece-wise linear resistance.

By defining the internal resistance as a function of the electric field Rint(E)R_{int}(E), the problem forces students to abandon standard load-line shortcuts and integrate the differential resistance to find the true non-linear V−IV-I characteristic.

Selecting the ideal Zener model or evaluating the resistance only at the onset voltage leads directly to the incorrect options.

Furthermore, the quadratic solution tests the student's ability to apply physical boundary conditions to reject the extraneous mathematical root.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptInternal Resistance Variation
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree