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Question #86986

Difficulty: 5/10 | 🟢 Free

The Question

An electron (mass mm, charge −e-e) moves in the xyxy-plane in a time-varying, space-dependent magnetic field B⃗=βt(ra)nk^\vec{B} = \beta t \left(\frac{r}{a}\right)^n \hat{k}, where β,a,n\beta, a, n are positive constants, tt is time, and rr is the distance from the origin. The electron's motion is a slow spiral, approximated as a circular orbit of slowly changing radius r(t)r(t) centered at the origin. Assuming the radial acceleration is negligible compared to the centripetal acceleration, which of the following gives the magnitude of the induced electric field EE at radius rr, and the rate of change of the electron's orbital magnetic dipole moment dμdt\frac{d\mu}{dt}?

Options

  • A.

    E=βrn+1an(n+2)E = \frac{\beta r^{n+1}}{a^n (n+2)}, dμdt=0\frac{d\mu}{dt} = 0

  • B.

    E=βrn+12anE = \frac{\beta r^{n+1}}{2 a^n}, dμdt=e2βrn+22man\frac{d\mu}{dt} = \frac{e^2 \beta r^{n+2}}{2 m a^n}

  • C.

    E=βrn+1an(n+2)E = \frac{\beta r^{n+1}}{a^n (n+2)}, dμdt=e2βrn+22man\frac{d\mu}{dt} = \frac{e^2 \beta r^{n+2}}{2 m a^n}

  • D.

    E=βrn+1an(n+1)E = \frac{\beta r^{n+1}}{a^n (n+1)}, dμdt=0\frac{d\mu}{dt} = 0

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Magnetic Dipole Moment of Revolving Electron|Motional EMF for Arbitrary Shapes|Integration

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the rigorous application of Faraday's Law in a space-dependent magnetic field and the concept of adiabatic invariance.

A common trap is assuming the induced EMF can be calculated using Φ=B⋅πr2\Phi = B \cdot \pi r^2 as if the field were uniform, leading to an incorrect electric field.

Furthermore, students often mistakenly assume the orbital radius remains constant as the magnetic field increases, directly differentiating μ=e2Br22m\mu = \frac{e^2 B r^2}{2m} to find a non-zero dμdt\frac{d\mu}{dt}.

In reality, the coupling of the induced tangential electric field and the radial drift velocity creates a torque that shrinks the orbit at exactly the rate required to conserve the magnetic flux through the orbit, rendering the magnetic dipole moment an exact invariant (dμdt=0\frac{d\mu}{dt} = 0).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMagnetism and Matter - Class 12
ConceptMagnetic Dipole Moment of Revolving Electron
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree