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Question #86141

Difficulty: 5/10 | 🟢 Free

The Question

A parallel-plate capacitor is completely filled with a solid isotropic dielectric and has an initial capacitance C0C_0 and initial volume V0V_0 at temperature T0T_0. The capacitor is charged to a constant charge QQ and then electrically isolated. The dielectric has a heat capacity at constant pressure CpC_p (measured when uncharged), a volume thermal expansion coefficient γ\gamma, and its permittivity varies with temperature as ϵ(T)=ϵi[1−β(T−T0)]\epsilon(T) = \epsilon_i [1 - \beta (T - T_0)], where β>0\beta > 0. The capacitor is kept in an environment at a constant atmospheric pressure P0P_0. The conducting plates are thin, perfectly flexible, and rigidly attached to the dielectric, expanding isotropically with it. If the temperature of the system is increased by a small amount ΔT\Delta T, which of the following expressions gives the total heat ΔQheat\Delta Q_{heat} supplied to the system? (Assume linear approximations hold for small ΔT\Delta T and ignore the heat capacity of the thin plates).

Options

  • A.

    [Cp+Q22C0(β−γ3)]ΔT\left[ C_p + \frac{Q^2}{2C_0} \left( \beta - \frac{\gamma}{3} \right) \right] \Delta T

  • B.

    [Cp+Q22C0β]ΔT\left[ C_p + \frac{Q^2}{2C_0} \beta \right] \Delta T

  • C.

    [Cp+Q22C0(β−4γ3)]ΔT\left[ C_p + \frac{Q^2}{2C_0} \left( \beta - \frac{4\gamma}{3} \right) \right] \Delta T

  • D.

    [Cp+P0V0γ+Q22C0(β−γ3)]ΔT\left[ C_p + P_0 V_0 \gamma + \frac{Q^2}{2C_0} \left( \beta - \frac{\gamma}{3} \right) \right] \Delta T

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Energy Density Locality|Thermal Expansion of Area and Volume|Integration

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the rigorous coupling of thermodynamics and electrostatics, specifically the First Law applied to a system with temperature-dependent geometry and permittivity.

Trap 1 (Option C) is the 'Energy Density Locality' trap: students misapply the energy density formula uE=12D2/ϵu_E = \frac{1}{2}D^2/\epsilon, calculate the change in local energy density ΔuE\Delta u_E, and multiply by the initial volume V0V_0, forgetting that the integration boundary (the volume itself) also expands.

Trap 2 (Option D) tests thermodynamic double-counting: students explicitly add the external work P0ΔVP_0 \Delta V to the heat equation, failing to realize it is already absorbed in the constant-pressure heat capacity CpC_p.

Trap 3 (Option B) assumes capacitance only changes due to permittivity, ignoring the geometric thermal expansion entirely.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptEnergy Density Locality
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree