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Question #85945

Difficulty: 5/10 | 🟢 Free

The Question

A circular mesoscopic ring of radius rr is placed in a uniform magnetic field B(t)B(t) perpendicular to its plane. The magnetic field varies with time tt as follows: it increases linearly from 00 to B0B_0 in time T0T_0, and then immediately decreases linearly from B0B_0 back to 00 in time T0/2T_0/2. Due to the discrete nature of the lattice, continuous eddy currents do not flow. Instead, charge transport occurs via discrete quantum hops. The number of electrons dNdN that complete a full revolution around the ring during a time interval dtdt is given by dN=1Φ0∣dΦdt∣dtdN = \frac{1}{\Phi_0} \left| \frac{d\Phi}{dt} \right| dt, where Φ(t)\Phi(t) is the magnetic flux and Φ0\Phi_0 is a fundamental flux constant. The energy dissipated by each electron during one revolution is equal to the work done on it by the induced electromotive force (EMF). Which of the following expressions gives the total energy dissipated in the ring during the entire time interval t=0t=0 to t=1.5T0t=1.5T_0?

Options

  • A.

    3eπ2r4B02Φ0T0\frac{3 e \pi^2 r^4 B_0^2}{\Phi_0 T_0}

  • B.

    8eπ2r4B023Φ0T0\frac{8 e \pi^2 r^4 B_0^2}{3 \Phi_0 T_0}

  • C.

    2eπ2r4B02Φ0T0\frac{2 e \pi^2 r^4 B_0^2}{\Phi_0 T_0}

  • D.

    00

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Quantization of Charge|Magnetic Flux Scalar Sign|Eddy Currents Dissipation

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the student's ability to transition from classical continuous macroscopic electrodynamics to a mesoscopic discrete charge transport model.

The primary trap lies in the scalar sign of the magnetic flux and the non-linear dependence of dissipation on the rate of change of flux.

Students might incorrectly assume that since the net change in magnetic flux over the entire cycle is zero, the total energy dissipated is zero (Option D).

Alternatively, they might calculate the average EMF over the entire 1.5T01.5T_0 interval and use it to find the total work, ignoring that Joule heating depends on the square of the instantaneous EMF (Option B).

By forcing the derivation of power from discrete quantum hops (P=dNdtWP = \frac{dN}{dt} W), the problem ensures students cannot blindly apply P=E2/RP = \mathcal{E}^2/R without proving the effective resistance Reff=Φ0/eR_{eff} = \Phi_0/e and correctly integrating the piecewise constant power.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptQuantization of Charge
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree