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Question #85060
The Question
A heavy, thick wire of total mass , length , and uniform cross-sectional area is suspended vertically from a rigid support. The material of the wire has a Young's modulus . The linear mass density of the wire is not uniform; it varies with the downward vertical distance from the top support according to the relation , where is a positive constant. If is the acceleration due to gravity, what is the total elongation of the wire due to its own weight?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Wire Elongation under Self-Weight|Continuous Charge Distribution|Integration
Why This Question Is Tricky
Examiner Levers
Visualization Stress
Requires mental rotation or 3D mapping (Optics/Geometry/Vectors).
Difficulty Boost : +4Boundary Condition
Tests behavior at limits like 0, 1, infinity, or empty sets.
Difficulty Boost : +4Dimensional Analysis
Tests if the student verifies units/dimensions before selecting.
Difficulty Boost : +2Common Mistakes
This question tests the student's ability to apply Hooke's Law to a continuous system with a non-uniform mass distribution.
A common trap is blindly applying the standard formula for a uniform wire () without recognizing that the variable density shifts the effective center of gravity.
Another frequent mistake is setting up the tension integral incorrectly by integrating from the top ( to ) instead of calculating the weight of the segment strictly below the cross-section ( to ), which yields the inverted result .
Students must construct the local stress-strain relationship from first principles and execute the boundary conditions properly.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Mechanical Properties of Solids - Class 11 Part 2 |
| Concept | Wire Elongation under Self-Weight |
| Difficulty | 8 |
| Cognitive Load | 8 |
| Target Solve Time | 180 sec |
| Access | Free |