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Question #84309

Difficulty: 5/10 | 🟢 Free

The Question

A simple pendulum consists of a small bob of mass mm and positive charge +q+q suspended by a massless, inextensible string of length LL. The pendulum is attached to the upper plate of a horizontal parallel-plate capacitor with plate separation dd. The capacitor is connected to an ideal battery of constant voltage VV, such that the upper plate is maintained at a positive potential relative to the lower plate. The entire setup is located in a mine at a depth h=R/2h = R/2 below the Earth's surface, where RR is the radius of the Earth and gg is the acceleration due to gravity at the surface. It is given that qV=12mgdqV = \frac{1}{2} mgd. Initially, the space between the plates is vacuum. A solid, uncharged dielectric slab of dielectric constant K=3K = 3 and thickness d/2d/2 is then slowly inserted and placed on the lower plate. Assuming the pendulum bob always oscillates in the vacuum region (L<d/2L < d/2) and edge effects are negligible, what is the new time period of small oscillations of the pendulum?

Options

  • A.

    4π5Lg\frac{4\pi}{\sqrt{5}} \sqrt{\frac{L}{g}}

  • B.

    2πLg2\pi \sqrt{\frac{L}{g}}

  • C.

    4π7Lg\frac{4\pi}{\sqrt{7}} \sqrt{\frac{L}{g}}

  • D.

    π6Lg\pi \sqrt{\frac{6L}{g}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Simple Pendulum Small Angle Approximation|Gravitational Field Variation|Dielectric Slab Displacement

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This problem tests the synthesis of gravitation, electrostatics, and simple harmonic motion.

The primary trap lies in the misapplication of capacitor principles when a dielectric is inserted.

Students often erroneously assume that because the capacitor is connected to a constant voltage source, the electric field in the vacuum region remains V/dV/d (leading to Option B).

Alternatively, they might confuse the setup with an isolated capacitor and assume the field decreases by a factor of KK (leading to Option D).

Furthermore, forgetting the linear variation of gravity with depth inside the Earth traps students into using surface gravity gg (leading to Option C).

The correct approach requires recognizing that the constant potential difference is redistributed across the vacuum and dielectric layers, increasing the field in the vacuum region and thus modulating the pendulum's effective restoring force.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptSimple Pendulum Small Angle Approximation
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree