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Question #84100

Difficulty: 5/10 | 🟢 Free

The Question

A spherical protostar of mass MM and instantaneous radius RR is undergoing a slow, quasi-static gravitational contraction. The density profile of the protostar is non-uniform and given by ρ(r)=cr\rho(r) = \frac{c}{r}, where cc is a positive constant and rr is the radial distance from the center. The protostar contracts such that its radius decreases at a constant rate vv (i.e., dRdt=−v\frac{dR}{dt} = -v). Assuming the protostar remains in hydrostatic equilibrium such that the Virial theorem (2K+U=02K + U = 0) is always satisfied (where KK is the total internal kinetic energy and UU is the gravitational self-energy), and that all the mechanical energy lost during contraction is radiated away from its surface as a perfect blackbody, find the instantaneous surface temperature TT of the protostar. (Given: GG is the universal gravitational constant, σ\sigma is the Stefan-Boltzmann constant).

Options

  • A.

    (GM2v12πσR4)1/4\left( \frac{GM^2 v}{12\pi \sigma R^4} \right)^{1/4}

  • B.

    (3GM2v40πσR4)1/4\left( \frac{3GM^2 v}{40\pi \sigma R^4} \right)^{1/4}

  • C.

    (GM2v6πσR4)1/4\left( \frac{GM^2 v}{6\pi \sigma R^4} \right)^{1/4}

  • D.

    (3GM2v20πσR4)1/4\left( \frac{3GM^2 v}{20\pi \sigma R^4} \right)^{1/4}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Stefan-Boltzmann Power Law|Gravitational Self-Energy|Integration

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the synthesis of classical mechanics (gravitational self-energy of a continuous mass distribution), thermodynamics (Virial theorem), and radiation (Stefan-Boltzmann law).

It contains two primary traps.

Trap 1: Students often memorize the self-energy of a uniform sphere (U=−3GM2/5RU = -3GM^2/5R) and blindly apply it, ignoring the variable density profile ρ(r)=c/r\rho(r) = c/r.

Trap 2: Students may equate the rate of change of potential energy directly to the radiated power (P=−dU/dtP = -dU/dt), forgetting that half of the released gravitational potential energy must go into increasing the internal kinetic energy (heating the star) to maintain hydrostatic equilibrium, as dictated by the Virial theorem.

Falling for either or both traps leads directly to the incorrect options.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptStefan-Boltzmann Power Law
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree