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Question #82260

Difficulty: 8/10 | 🟢 Free

The Question

A parallel plate capacitor consists of two rectangular plates of length L=0.2 mL = 0.2 \text{ m} (along the xx-axis) and width W=0.1 mW = 0.1 \text{ m} (along the yy-axis), separated by a distance d=5 mmd = 5 \text{ mm} along the zz-axis. A constant potential difference V0=50 VV_0 = 50 \text{ V} is maintained across the plates. An ideal, incompressible dielectric fluid flows between the plates with a uniform velocity v⃗=2.0i^ m s−1\vec{v} = 2.0 \hat{i} \text{ m s}^{-1}. The permittivity of any individual fluid parcel remains constant as it moves (i.e., the material derivative DεDt=0\frac{D\varepsilon}{Dt} = 0). At a given instant t=0t=0, the permittivity of the fluid between the plates varies continuously along the xx-axis from ε1=3ε0\varepsilon_1 = 3\varepsilon_0 at the entrance (x=0x=0) to ε2=8ε0\varepsilon_2 = 8\varepsilon_0 at the exit (x=Lx=L), where ε0\varepsilon_0 is the vacuum permittivity. A uniform magnetic field B⃗=0.5i^ T\vec{B} = 0.5 \hat{i} \text{ T} is also present. What is the magnitude of the total displacement current through the capacitor at t=0t=0?

Options

  • A.

    1.0×104ε0 V m s−11.0 \times 10^4 \varepsilon_0 \text{ V m s}^{-1}

  • B.

    0 A0 \text{ A}

  • C.

    1.1×104ε0 V m s−11.1 \times 10^4 \varepsilon_0 \text{ V m s}^{-1}

  • D.

    1.6×104ε0 V m s−11.6 \times 10^4 \varepsilon_0 \text{ V m s}^{-1}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Equation of Continuity|Ampere’s Law Displacement Current|Non-Uniform Dielectric Filling

Why This Question Is Tricky

Examiner Levers

Extraneous Data

Provides unnecessary variables (Red Herrings) to test conceptual focus.

Difficulty Boost : +3

Visualization Stress

Requires mental rotation or 3D mapping (Optics/Geometry/Vectors).

Difficulty Boost : +4

Concept Bridge

Cross-chapter synthesis (e.g., using Logarithms in Electrochemistry).

Difficulty Boost : +5

Common Mistakes

The question tests the generalized Ampere-Maxwell law in the presence of a moving, inhomogeneous dielectric.

Students commonly memorize displacement current as Id=CdVdtI_d = C \frac{dV}{dt} and incorrectly conclude that a constant voltage implies zero displacement current (Option B).

This ignores the polarization/motional current component E⃗∂ε∂t\vec{E} \frac{\partial \varepsilon}{\partial t} arising from the advection of the dielectric fluid.

By coupling Maxwell's equations with the fluid continuity equation (material derivative DεDt=0\frac{D\varepsilon}{Dt} = 0), the student must recognize that the local time derivative of permittivity is driven by the spatial gradient and fluid velocity, leading to a non-zero displacement current despite the static electric field.

The magnetic field is a red herring designed to test if students incorrectly apply Lorentz force transformations when v⃗∥B⃗\vec{v} \parallel \vec{B}.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Fluids - Class 11 Part 2
ConceptEquation of Continuity
Difficulty8
Cognitive Load8
Target Solve Time180 sec
AccessFree