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Question #79715

Difficulty: 5/10 | 🟢 Free

The Question

A micro-submarine navigates in a 2D fluid flow. The fluid velocity field is given by v⃗f=−∇Φ\vec{v}_f = -\nabla \Phi, where the scalar potential is Φ(x,y)=k(x2−y2)\Phi(x,y) = k(x^2 - y^2) and kk is a positive constant with units of s−1\text{s}^{-1}. The submarine moves from point A(R,0)A(R, 0) to point B(0,R)B(0, R) along a quarter-circular path x2+y2=R2x^2 + y^2 = R^2 in the first quadrant, where RR is in meters. The submarine's absolute velocity v⃗\vec{v} (velocity with respect to the stationary ground) is maintained such that its magnitude is a constant v0v_0 (in m/s\text{m/s}) and it is always directed tangentially along the path from AA to BB. The fluid exerts a drag force on the submarine given by F⃗d=−bv⃗r\vec{F}_d = -b \vec{v}_r, where bb is a positive constant with units of kg⋅s−1\text{kg} \cdot \text{s}^{-1} and v⃗r\vec{v}_r is the velocity of the submarine relative to the fluid. The submarine's internal engine provides a thrust F⃗t\vec{F}_t to exactly balance the drag force at all times (assume no other forces act in the plane of motion). Calculate the total work WtW_t done by the engine as the submarine moves from AA to BB.

Options

  • A.

    bR(πv02−2kR)b R \left( \frac{\pi v_0}{2} - 2k R \right)

  • B.

    bR(πv02+2kR)b R \left( \frac{\pi v_0}{2} + 2k R \right)

  • C.

    bR(2v0−2kR)b R \left( \sqrt{2} v_0 - 2k R \right)

  • D.

    bR2(πv02−2kR)b R^2 \left( \frac{\pi v_0}{2} - 2k R \right)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Rain-Man/Swimmer Logic|Conservative Field Path Independence|Vector Calculus

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the application of the Fundamental Theorem of Line Integrals to a velocity field rather than a force field.

Students often fall into the trap of manually parameterizing the complex path to integrate the drag force, which is time-consuming and highly prone to sign errors.

The elegant 'Swimmer Logic' separates the integral into an absolute path integral and a fluid drift integral.

Because the fluid velocity is the gradient of a scalar potential (v⃗f=−∇Φ\vec{v}_f = -\nabla \Phi), its line integral is path-independent and simplifies to the scalar potential difference.

Additionally, Option D serves as a dimensional analysis trap (yielding units of ML3T−2M L^3 T^{-2} instead of Work), rewarding students who verify dimensional consistency before calculating.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Plane - Class 11 Part 1
ConceptRain-Man/Swimmer Logic
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree