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Question #77930

Difficulty: 5/10 | 🟢 Free

The Question

A spherical particle of radius r=1.00×10−3 mr = 1.00 \times 10^{-3} \text{ m} falls at a constant terminal velocity vtv_t through a viscous liquid. The measured weight of the particle is W=3.56×10−3 NW = 3.56 \times 10^{-3} \text{ N} and the measured buoyant force exerted by the liquid is Fb=1.4×10−3 NF_b = 1.4 \times 10^{-3} \text{ N}. The dynamic viscosity of the liquid is η=0.796 Pa⋅s\eta = 0.796 \text{ Pa}\cdot\text{s}. Assuming Stokes' law is valid and treating π\pi as an exact number, what is the terminal velocity vtv_t of the particle, expressed with the correct number of significant figures?

Options

  • A.

    0.15 m/s0.15 \text{ m/s}

  • B.

    0.144 m/s0.144 \text{ m/s}

  • C.

    0.14 m/s0.14 \text{ m/s}

  • D.

    0.147 m/s0.147 \text{ m/s}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Significant Figures in Mixed Operations|Viscosity and Stokes' Law

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the student's ability to correctly apply the hierarchy of significant figure rules across mixed operations (addition/subtraction followed by multiplication/division) in a physical context.

Students commonly fall into the trap of treating the entire terminal velocity equation as a single continuous calculation, failing to round the intermediate force subtraction.

If they subtract 3.56−1.4=2.163.56 - 1.4 = 2.16 and carry 2.162.16 (which they incorrectly assume has 3 sig figs) into the division, they arrive at 0.144 m/s0.144 \text{ m/s} or 0.14 m/s0.14 \text{ m/s}.

By forcing the intermediate rounding via the decimal-place rule for subtraction, the net force drops to 2 significant figures (2.22.2), which then dictates the precision of the final division, yielding 0.15 m/s0.15 \text{ m/s}.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptSignificant Figures in Mixed Operations
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree