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Question #77790

Difficulty: 8/10 | 🟢 Free

The Question

A water tank has a non-uniform cross-sectional area given by A(h)=khA(h) = k \sqrt{h}, where hh is the height of the water level from the bottom and kk is a positive constant with appropriate SI units. A small hole of area aa is opened at the bottom (h=0h=0). A student calculates the time T0T_0 required for the water level to drop from h=Hh = H to h=H/2h = H/2 by assuming the efflux velocity is exactly given by Torricelli's law, v=2ghv = \sqrt{2gh}. However, the true time TT differs because the downward velocity of the free surface is not strictly zero. Assuming a≪kHa \ll k\sqrt{H}, which of the following expressions best represents the fractional error T0−TT0\frac{T_0 - T}{T_0} in the student's calculation?

Options

  • A.

    a2ln⁡2k2H\frac{a^2 \ln 2}{k^2 H}

  • B.

    a22k2H\frac{a^2}{2 k^2 H}

  • C.

    a2ln⁡22k2H\frac{a^2 \ln 2}{2 k^2 H}

  • D.

    2a2ln⁡2k2H\frac{2 a^2 \ln 2}{k^2 H}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Torricelli’s Efflux Velocity|Relative Error Propagation in Powers|Equation of Continuity

Why This Question Is Tricky

Examiner Levers

Visualization Stress

Requires mental rotation or 3D mapping (Optics/Geometry/Vectors).

Difficulty Boost : +4

Common Mistakes

This question tests the limits of Torricelli's law and the propagation of approximations through a differential equation.

Students often memorize v=2ghv = \sqrt{2gh} without recognizing it assumes an infinitely large tank cross-section (A≫aA \gg a).

When the tank has a tapering profile A(h)=khA(h) = k\sqrt{h}, the finite velocity of the free surface introduces a height-dependent correction term to the efflux velocity.

The trap lies in attempting to apply a static error percentage at the end of the calculation rather than correctly applying the binomial expansion (1−x)1/2≈1−x/2(1 - x)^{1/2} \approx 1 - x/2 to the differential equation −A(h)dh=av(h)dt-A(h)dh = av(h)dt before integrating.

This highlights the non-linear coupling between the dynamic cross-sectional area and the fluid continuity equation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptRelative Error Propagation in Powers
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree