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Question #77790
The Question
A water tank has a non-uniform cross-sectional area given by , where is the height of the water level from the bottom and is a positive constant with appropriate SI units. A small hole of area is opened at the bottom (). A student calculates the time required for the water level to drop from to by assuming the efflux velocity is exactly given by Torricelli's law, . However, the true time differs because the downward velocity of the free surface is not strictly zero. Assuming , which of the following expressions best represents the fractional error in the student's calculation?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Torricelli’s Efflux Velocity|Relative Error Propagation in Powers|Equation of Continuity
Why This Question Is Tricky
Examiner Levers
Visualization Stress
Requires mental rotation or 3D mapping (Optics/Geometry/Vectors).
Difficulty Boost : +4Common Mistakes
This question tests the limits of Torricelli's law and the propagation of approximations through a differential equation.
Students often memorize without recognizing it assumes an infinitely large tank cross-section ().
When the tank has a tapering profile , the finite velocity of the free surface introduces a height-dependent correction term to the efflux velocity.
The trap lies in attempting to apply a static error percentage at the end of the calculation rather than correctly applying the binomial expansion to the differential equation before integrating.
This highlights the non-linear coupling between the dynamic cross-sectional area and the fluid continuity equation.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Units and Measurements - Class 11 Part 1 |
| Concept | Relative Error Propagation in Powers |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |