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Question #77498
The Question
A small bar magnet of mass and magnetic dipole moment falls under gravity along the axis of a fixed horizontal circular conducting ring of radius and electrical resistance . The magnetic dipole moment remains aligned with the vertical axis (-axis) throughout the motion. The self-inductance of the ring is negligible. At a specific height above the center of the ring, the magnet is observed to fall with zero acceleration. What is the velocity of the magnet at this instant? (Assume the magnetic field of the magnet is that of an ideal point dipole, and the acceleration due to gravity is .)
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Relative Velocity in 1D|Lenz’s Law Energy Conservation|Induced Electric Fields
Why This Question Is Tricky
Examiner Levers
Dimensional Analysis
Tests if the student verifies units/dimensions before selecting.
Difficulty Boost : +2Common Mistakes
This problem tests the student's ability to model velocity-dependent inductive drag by coupling Faraday's Law with Newtonian dynamics.
A common trap is failing to square the flux gradient when equating mechanical power to electrical power (), which leads to dimensionally incorrect linear dependencies (Option D).
Another trap is misapplying Ohm's law by placing resistance in the denominator of the velocity expression (Option C), or evaluating the flux gradient at an incorrect position like (Option B).
The core physical principle requires recognizing that the back-EMF acts as a non-conservative damping force , necessitating a strict energy-conservation approach to find the terminal state.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Motion in a Straight Line - Class 11 Part 1 |
| Concept | Relative Velocity in 1D |
| Difficulty | 5 |
| Cognitive Load | 6 |
| Target Solve Time | 140 sec |
| Access | Free |