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Question #76203

Difficulty: 8/10 | 🟢 Free

The Question

Let a⃗,b⃗,c⃗,d⃗\vec{a}, \vec{b}, \vec{c}, \vec{d} be any four vectors in R3\mathbb{R}^3. Consider the determinant Δ=∣a⃗⋅c⃗a⃗⋅d⃗[a⃗,c⃗,d⃗]b⃗⋅c⃗b⃗⋅d⃗[b⃗,c⃗,d⃗][c⃗,b⃗,a⃗][d⃗,b⃗,a⃗](b⃗×a⃗)⋅(c⃗×d⃗)∣\Delta = \begin{vmatrix} \vec{a}\cdot\vec{c} & \vec{a}\cdot\vec{d} & [\vec{a}, \vec{c}, \vec{d}] \\ \vec{b}\cdot\vec{c} & \vec{b}\cdot\vec{d} & [\vec{b}, \vec{c}, \vec{d}] \\ [\vec{c}, \vec{b}, \vec{a}] & [\vec{d}, \vec{b}, \vec{a}] & (\vec{b}\times\vec{a})\cdot(\vec{c}\times\vec{d}) \end{vmatrix} where [x⃗,y⃗,z⃗][\vec{x}, \vec{y}, \vec{z}] denotes the scalar triple product. Which of the following is identically equal to Δ\Delta?

Options

  • A.

    ∣a⃗×b⃗∣2∣c⃗×d⃗∣2|\vec{a}\times\vec{b}|^2 |\vec{c}\times\vec{d}|^2

  • B.

    −∣a⃗×b⃗∣2∣c⃗×d⃗∣2-|\vec{a}\times\vec{b}|^2 |\vec{c}\times\vec{d}|^2

  • C.

    ((a⃗×b⃗)⋅(c⃗×d⃗))2((\vec{a}\times\vec{b})\cdot(\vec{c}\times\vec{d}))^2

  • D.

    −((a⃗×b⃗)⋅(c⃗×d⃗))2- ((\vec{a}\times\vec{b})\cdot(\vec{c}\times\vec{d}))^2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Vector Product Anti-Commutativity|Determinant Product Rule

Why This Question Is Tricky

Examiner Levers

Variable Manipulation

Algebraic solutions only (No numbers); tests pure symbolic logic.

Difficulty Boost : +4

Common Mistakes

This question tests the student's mastery of the Determinant Product Rule (Gram determinant extension) and the anti-commutativity of the vector cross product.

The core trap lies in the evaluation of the scalar triple product [a⃗,b⃗,b⃗×a⃗][\vec{a}, \vec{b}, \vec{b}\times\vec{a}].

Students frequently memorize the identity [x⃗,y⃗,x⃗×y⃗]=∣x⃗×y⃗∣2[\vec{x}, \vec{y}, \vec{x}\times\vec{y}] = |\vec{x}\times\vec{y}|^2 and hastily apply it without noticing the reversed order of vectors in the cross product.

By expressing the determinant as the product of two matrices, the row-swapping property forces a negative sign, yielding −∣a⃗×b⃗∣2-|\vec{a}\times\vec{b}|^2.

Failing to account for this sign inversion leads directly to the incorrect positive magnitude squared option.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterVector Algebra - Class 12
ConceptVector Product Anti-Commutativity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree