Before You Begin
Question #76005
The Question
Let and be two unit vectors such that the angle between them is , where . Let be the plane passing through the origin, containing the vector , and perpendicular to the plane containing and . Let be the plane passing through the origin, containing the vector , and perpendicular to the plane containing and . If is the acute angle between the planes and , then is equal to:
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Vector Triple Product Expansion|Angle between two planes|Symmetric vs Non-symmetric form|ASTC Quadrant Sign Convention
Why This Question Is Tricky
Examiner Levers
Variable Manipulation
Algebraic solutions only (No numbers); tests pure symbolic logic.
Difficulty Boost : +4Common Mistakes
This question tests the intersection of Vector Triple Product (VTP) expansions and 3D geometry, specifically targeting the definition of the angle between two planes.
Students must first correctly apply the VTP to find the normal vectors of planes defined in non-symmetric form.
The primary trap lies in the ASTC quadrant sign convention combined with the definition of the acute angle between planes.
The dot product of the normals yields .
Because , is negative, meaning the angle between the normals is obtuse.
Students who blindly equate the angle between normals to the angle between planes will incorrectly choose .
The true acute angle requires taking the absolute value, yielding .
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Vector Algebra - Class 12 |
| Concept | Vector Triple Product Expansion |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |