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Question #74549

Difficulty: 8/10 | 🟢 Free

The Question

Let L1L_1 and L2L_2 be two skew lines in R3\mathbb{R}^3 with direction vectors b⃗1\vec{b}_1 and b⃗2\vec{b}_2, passing through points with position vectors a⃗1\vec{a}_1 and a⃗2\vec{a}_2 respectively. Let c⃗=a⃗2−a⃗1\vec{c} = \vec{a}_2 - \vec{a}_1. A 3×33 \times 3 matrix AA is constructed such that its first, second, and third rows are the components of c⃗\vec{c}, b⃗1\vec{b}_1, and b⃗2\vec{b}_2 respectively. Let C=adj(AAT)C = \text{adj}(A A^T) be the adjugate matrix of AATA A^T. If c11c_{11} denotes the entry in the first row and first column of CC, which of the following expressions represents the shortest distance between the lines L1L_1 and L2L_2?

Options

  • A.

    (det⁡C)1/4c11\frac{(\det C)^{1/4}}{\sqrt{c_{11}}}

  • B.

    det⁡Cc11\frac{\sqrt{\det C}}{c_{11}}

  • C.

    (det⁡C)1/4c11\frac{(\det C)^{1/4}}{c_{11}}

  • D.

    det⁡Cc11\frac{\sqrt{\det C}}{\sqrt{c_{11}}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Shortest distance between skew lines|Scalar Triple Product Volume Logic|Determinant Product Rule

Why This Question Is Tricky

Examiner Levers

Variable Manipulation

Algebraic solutions only (No numbers); tests pure symbolic logic.

Difficulty Boost : +4

Common Mistakes

This question tests the synthesis of 3D geometry and linear algebra by obfuscating the standard shortest distance formula within matrix operations.

The primary trap lies in recognizing that the scalar triple product is the determinant of matrix AA, and forcing the use of the Determinant Product Rule to relate det⁡(A)\det(A) to the adjugate of the Gram matrix AATA A^T.

Students commonly fail to identify that the cofactor c11c_{11} of the Gram matrix represents Lagrange's identity for the squared magnitude of the cross product ∣b⃗1×b⃗2∣2|\vec{b}_1 \times \vec{b}_2|^2.

Furthermore, a frequent algebraic mistake is misapplying the adjugate determinant property, incorrectly assuming det⁡(adj(M))=det⁡(M)\det(\text{adj}(M)) = \det(M) instead of (det⁡M)2(\det M)^2 for a 3×33 \times 3 matrix, which leads to incorrect powers in the numerator.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptShortest distance between skew lines
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree