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Question #74475
The Question
Let the equation of a plane be , where is the perpendicular distance of the plane from the origin (). It is given that , , and for some real . The plane passes through the point .
A line lies entirely in the plane . If the line is perpendicular to the vector , then the value of is:
Options
- A.
21
- B.
25
- C.
19
- D.
23
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Coplanarity Condition|Line lying in a plane|Normal Form Parameters|Domain Constraint Intersections
Why This Question Is Tricky
Examiner Levers
Recursive Logic
The answer to part A is required to solve part B (Step-wise failure test).
Difficulty Boost : +5Common Mistakes
The question tests the student's understanding of the normal form of a plane equation and the coplanarity conditions for a line.
The primary trap is the assumption that in are mere direction ratios.
By explicitly defining as the perpendicular distance from the origin, the coefficients are forced to be direction cosines, invoking the hidden constraint .
This constraint intersects with the domain and range properties of inverse trigonometric functions to uniquely determine the plane's normal vector.
Students who miss this will be unable to find and will fail the subsequent coplanarity tests.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Vector Algebra - Class 12 |
| Concept | Coplanarity Condition |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 170 sec |
| Access | Free |