Before You Begin
Question #74453
The Question
Let and be three variable vectors such that their scalar triple product is given by:\n[\\vec{u}(x), \\vec{v}(x), \\vec{w}(x)] = \\frac{1}{14} \\begin{vmatrix} 1 & 1 & 1 \\\\ x & 13 & 27 \\\\ x^2 & 169 & 729 \\end{vmatrix} - 24 \\text{sgn}(x - 20)\nwhere denotes the signum function. An objective function representing the accumulated volume is defined as . If and are the points of local maximum and local minimum of respectively in the interval , find the value of .
Options
- A.
298
- B.
218
- C.
351
- D.
322
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Coplanarity Condition|Factor Theorem in Determinants|Signum Function Discontinuity|Objective Function Gradient
Why This Question Is Tricky
Examiner Levers
Recursive Logic
The answer to part A is required to solve part B (Step-wise failure test).
Difficulty Boost : +5Common Mistakes
This question tests the student's ability to handle piecewise gradients defined by signum functions within an integral objective function.
The primary trap lies in the evaluation of the scalar triple product determinant using the Factor Theorem, which yields a continuous polynomial .
Students often ignore the domain restrictions imposed by the term, incorrectly assuming the critical points of the objective function are simply the roots of the polynomial (13 and 27).
Furthermore, the discontinuity at creates a piecewise derivative; students must correctly reject the extraneous roots ( for the left branch and for the right branch) by strictly checking the boundary conditions of each interval.
Finally, they must verify that the non-differentiable point is not an extremum since the gradient does not change sign across the jump discontinuity.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Vector Algebra - Class 12 |
| Concept | Coplanarity Condition |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 170 sec |
| Access | Free |