Start Learning Free

Before You Begin

Question #74428

Difficulty: 8/10 | 🟢 Free

The Question

Let C1C_1 be the hyperbola defined by the position vector r⃗(θ)=asec⁡θi^+atan⁡θj^\vec{r}(\theta) = a \sec \theta \hat{i} + a \tan \theta \hat{j} for a>0a > 0. At θ=π/4\theta = \pi/4, let T⃗\vec{T} be the tangent vector to C1C_1. A normal vector to C1C_1 at this point is defined by the vector triple product N⃗1=T⃗×(r⃗×T⃗)\vec{N}_1 = \vec{T} \times (\vec{r} \times \vec{T}).

Let C2C_2 be the curve defined by y=2ln⁡(x2−b2)y = \sqrt{2} \ln(x^2 - b^2), where b>0b > 0. Let SS be the set of all valid xx-coordinates on C2C_2 at which the normal vector to C2C_2 is parallel to N⃗1\vec{N}_1. Find the sum of the elements in SS.

Options

  • A.

    2

  • B.

    1+1+b21 + \sqrt{1 + b^2}

  • C.

    1−1+b21 - \sqrt{1 + b^2}

  • D.

    21+b22\sqrt{1 + b^2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Vector Triple Product Expansion|Normal to Conic|Logarithmic Differentiation Domain|Slope Sensitivity

Why This Question Is Tricky

Examiner Levers

Logical Assertion

Tests the causal relationship between two true statements.

Difficulty Boost : +4

Variable Manipulation

Algebraic solutions only (No numbers); tests pure symbolic logic.

Difficulty Boost : +4

Recursive Logic

The answer to part A is required to solve part B (Step-wise failure test).

Difficulty Boost : +5

Common Mistakes

This question tests the intersection of vector geometry and calculus domains.

Students must first correctly expand the Vector Triple Product to find the normal slope, leading to the quadratic equation x2−2x−b2=0x^2 - 2x - b^2 = 0.

The critical trap lies in the domain of logarithmic differentiation: y=2ln⁡(x2−b2)y = \sqrt{2} \ln(x^2 - b^2) strictly requires ∣x∣>b|x| > b.

Students who blindly sum the roots using Vieta's formulas will get 2 (Option A), failing to reject the extraneous root x=1−1+b2x = 1 - \sqrt{1 + b^2} which violates the domain constraint.

This simulates the classic JEE Advanced mechanism of 'ghost solutions' generated by algebraic manipulation of restricted functions.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterVector Algebra - Class 12
ConceptVector Triple Product Expansion
Difficulty8
Cognitive Load8
Target Solve Time180 sec
AccessFree