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Question #72214
The Question
Let be the vector space of all real matrices. Let be a matrix whose characteristic polynomial is and whose minimal polynomial is . Consider the system of differential equations given by the operator equation , where . Let be the subspace of solutions of the form , where is a constant non-zero matrix and . What is the dimension of ?
Options
- A.
3
- B.
5
- C.
6
- D.
9
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Exact Differential Recognition|Linear Independence vs Dependence|Characteristic Equation
Why This Question Is Tricky
Examiner Levers
Variable Manipulation
Algebraic solutions only (No numbers); tests pure symbolic logic.
Difficulty Boost : +4Common Mistakes
This question tests the student's ability to analyze a matrix differential equation by treating the commutator as a linear operator.
The primary trap is assuming the solution space dimension is either 3 (confusing matrix ODEs with vector ODEs) or 9 (assuming the operator is diagonalizable since its only eigenvalue is 0).
Another trap is incorrectly calculating the dimension of the commutant by assuming a single Jordan block, which would yield a dimension of 3.
By specifying the minimal polynomial as , the problem forces students to construct the correct Jordan canonical form and apply the Rank-Nullity theorem to find the exact geometric multiplicity of the operator, which is 5.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Exact Differential Recognition |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |