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Question #72147

Difficulty: 8/10 | 🟢 Free

The Question

Let the plane PP be given by the equation ∣210x−1y−2z+1−10−1∣=0\begin{vmatrix} 2 & 1 & 0 \\ x-1 & y-2 & z+1 \\ -1 & 0 & -1 \end{vmatrix} = 0 Let the line LL be given by x−41=y−10=z−λ1\frac{x-4}{1} = \frac{y-1}{0} = \frac{z-\lambda}{1}. If the line LL is coplanar with the plane PP, let θ\theta be the acute angle between the plane PP and the line L′L' given by x7λ=y4=z8−12λ\frac{x}{7\lambda} = \frac{y}{4} = \frac{z}{8-12\lambda} Find the value of θ\theta.

Options

  • A.

    π6\frac{\pi}{6}

  • B.

    00

  • C.

    sin⁡−1(1930)\sin^{-1}\left(\frac{19}{30}\right)

  • D.

    sin⁡−1(430)\sin^{-1}\left(\frac{4}{\sqrt{30}}\right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Angle between line and plane|Coplanarity Condition|Minors and Cofactors Sign Convention

Why This Question Is Tricky

Examiner Levers

Recursive Logic

The answer to part A is required to solve part B (Step-wise failure test).

Difficulty Boost : +5

Common Mistakes

The problem tests the angle between a line and a plane, but the plane equation is given as a determinant.

The primary trap is the 'Minors and Cofactors' sign convention.

If a student expands the determinant along the second row but forgets the alternating signs (−1)i+j(-1)^{i+j} for cofactors C21C_{21} and C23C_{23}, they obtain an incorrect plane equation (x+2y−z−6=0x + 2y - z - 6 = 0) with normal ⟨1,2,−1⟩\langle 1, 2, -1 \rangle.

The problem forces a Coplanarity Condition check: the line LL is parallel to both the true and wrong planes, so the student must substitute a point to find λ\lambda.

The wrong plane yields λ=0\lambda = 0, which perfectly cascades into the second part, making the direction vector of L′L' orthogonal to the wrong normal, resulting in a trap answer of θ=0\theta = 0.

The correct expansion yields λ=4\lambda = 4 and θ=π/6\theta = \pi/6.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptAngle between line and plane
Difficulty8
Cognitive Load7
Target Solve Time170 sec
AccessFree