Before You Begin
Question #72142
The Question
Let a ray in the region be defined as the intersection of the plane and the locus of a point whose distance from the plane is equal to , where . If is the acute angle between the ray and the -plane, then is equal to:
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Angle between line and plane|Distance from point to plane|Modulus Sign Dependency
Why This Question Is Tricky
Examiner Levers
Variable Manipulation
Algebraic solutions only (No numbers); tests pure symbolic logic.
Difficulty Boost : +4Common Mistakes
This question tests the student's ability to handle modulus sign dependencies in 3D geometry.
When equating a distance (which inherently involves an absolute value) to a variable expression, an implicit domain constraint arises (here, ).
Squaring both sides to solve the equation introduces an extraneous root that corresponds to the negative branch of the modulus.
Students who blindly square the equation without checking the domain constraint will incorrectly select the slope , leading them straight to the trap option B.
Recognizing that the modulus dictates the valid geometric region is crucial for identifying the correct direction vector of the ray.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Three-Dimensional Geometry - Class 12 |
| Concept | Angle between line and plane |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |