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Question #71556

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=x−2af(x) = \sqrt{x - 2a} for x≥2ax \ge 2a, where a>0a > 0. Let h(x)=f−1(f(x))h(x) = f^{-1}(f(x)). Consider the family of curves Γ1\Gamma_1 satisfying the differential equation dydx=−12h(x)−2a\frac{dy}{dx} = \frac{-1}{2h(x) - 2a}. Let Γ2\Gamma_2 be the orthogonal trajectory of Γ1\Gamma_1 that passes through the point (3a,0)(3a, 0). Let RR be the sum of the xx-coordinates of all points where Γ2\Gamma_2 intersects the xx-axis. Let HH be the number of points where Γ2\Gamma_2 has a horizontal tangent. Find the value of R−aHR - aH.

Options

  • A.

    3a

  • B.

    a

  • C.

    2a

  • D.

    4a

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Orthogonal Trajectories|Rolle's Theorem Root Existence|Composition Inverse Identity Traps|Inverse Existence Criterion

Why This Question Is Tricky

Examiner Levers

Variable Manipulation

Algebraic solutions only (No numbers); tests pure symbolic logic.

Difficulty Boost : +4

Common Mistakes

This question tests the 'Inverse Identity Trap' combined with orthogonal trajectories and the existence of roots/horizontal tangents (Rolle's Theorem conditions).

Students commonly assume f−1(f(x))=xf^{-1}(f(x)) = x globally, ignoring that the identity only holds within the domain of the inner function f(x)f(x) (here, x≥2ax \ge 2a).

This false assumption leads to accepting 'ghost roots' (x=−ax = -a) and falsely applying Rolle's Theorem to find non-existent horizontal tangents (x=ax = a) that lie outside the valid domain of the orthogonal trajectory.

By forcing the evaluation of R−aHR - aH, the problem heavily penalizes the failure to apply global domain constraints to local derivative properties.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDifferential Equations - Class 12
ConceptOrthogonal Trajectories
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree