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Question #71547
The Question
Let be the surface defined by the position vector . A family of curves is generated by projecting the intersections of with the family of planes onto the -plane, where is a parameter.
Let be the family of orthogonal trajectories of in the -plane. Let be the specific curve in that passes through the point .
Evaluate the line integral where is traversed in the counter-clockwise direction.
Options
- A.
0
- B.
341
- C.
343
- D.
686
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Orthogonal Trajectories|Geometric Interpretation of Cross Product|Line lying in a plane|Parametric form pitfalls
Why This Question Is Tricky
Examiner Levers
Recursive Logic
The answer to part A is required to solve part B (Step-wise failure test).
Difficulty Boost : +5Common Mistakes
This question tests the geometric interpretation of vector-defined surfaces and the derivation of orthogonal trajectories.
The primary trap lies in the 'Parametric form pitfall' and loss of degrees of freedom: students might attempt to parameterize the 3D intersection curve and find orthogonal vectors in 3D space before projecting, which conflates the parameter of the curve with the parameter of the family, leading to an incorrect differential equation.
Furthermore, a secondary trap is embedded in the line integral: if a student fails to find the orthogonal trajectory and mistakenly uses the original curve (centered at ), Green's theorem yields .
The value 341 is included as a distractor for arithmetic errors near the calculation.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Orthogonal Trajectories |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 170 sec |
| Access | Free |