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Question #70184

Difficulty: 8/10 | 🟢 Free

The Question

Consider the family of curves given by the differential equation dydx=a2+sin⁡2xy−y3\frac{dy}{dx} = \frac{a^2+\sin^2 x}{y - y^3}, where a>0a > 0. Let y=f(x)y=f(x) be the orthogonal trajectory to this family. If f(0)=y0f(0) = y_0 (where y0∉{−1,0,1}y_0 \notin \{-1, 0, 1\}), find the value of lim⁡x→π∣1−(f(x))−2∣∣1−y0−2∣\lim_{x \to \pi} \frac{|1 - (f(x))^{-2}|}{|1 - y_0^{-2}|}.

Options

  • A.

    e2πaa2+1e^{\frac{2\pi}{a\sqrt{a^2+1}}}

  • B.

    1

  • C.

    eπaa2+1e^{\frac{\pi}{a\sqrt{a^2+1}}}

  • D.

    e2πa2+1e^{\frac{2\pi}{a^2+1}}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Orthogonal Trajectories|Partial Fractions Decomposition|ASTC Quadrant Sign Convention|Symmetry and Periodicity

Why This Question Is Tricky

Examiner Levers

Variable Manipulation

Algebraic solutions only (No numbers); tests pure symbolic logic.

Difficulty Boost : +4

Common Mistakes

This problem fuses orthogonal trajectories, partial fraction decomposition, and a lethal periodicity trap.

The integral ∫dxa2+sin⁡2x\int \frac{dx}{a^2+\sin^2 x} evaluates to an inverse tangent function with a restricted domain (−π/2,π/2)(-\pi/2, \pi/2).

Students who blindly apply the naive antiderivative without the step function ⌊x+π/2π⌋\lfloor \frac{x+\pi/2}{\pi} \rfloor will incorrectly evaluate the definite integral from 00 to π\pi as 00, leading to the trap answer 11.

Recognizing the asymptotes of tan⁡x\tan x and enforcing continuity is mandatory for the correct exponential ratio.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDifferential Equations - Class 12
ConceptOrthogonal Trajectories
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree