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Question #68612
The Question
Let be the set of all continuously differentiable functions satisfying and . Let be the region bounded by all the curves in . Let be the subset of consisting of functions that do NOT satisfy the condition , and let be the region bounded by the curves in . If and are the areas of regions and respectively, what is the value of ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Geometric Interpretation|Inequalities in Definite Integrals|Extraneous Solution Rejection|The Sign-Consistency Principle
Why This Question Is Tricky
Examiner Levers
Negative Thinking
Uses "NOT", "EXCEPT", or "INCORRECT" to flip the logic gate.
Difficulty Boost : +2Common Mistakes
This question tests the student's ability to handle absolute value ODEs and extraneous solutions combined with integral inequalities (Sign-Consistency Principle).
The ODE implies .
Because must be continuous, it can only change signs at the roots of , specifically at .
This creates 4 distinct valid branches for .
Students often fail to identify all 4 branches, assuming must be uniformly or , which would yield an incorrect total area .
Furthermore, the negative phrasing 'do NOT satisfy' forces students to correctly evaluate the integral inequality to isolate the specific subset .
Failing to apply the sign-consistency check or misinterpreting the geometric boundaries of the piecewise functions leads to incorrect area calculations.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Geometric Interpretation |
| Difficulty | 5 |
| Cognitive Load | 6 |
| Target Solve Time | 140 sec |
| Access | Free |