Before You Begin
Question #68598
The Question
Let be a family of curves satisfying the differential equation , where is a parameter. For each , the curve passes through the origin. Let be the point of local extremum of the curve . As varies, traces a curve . A new curve is defined as the locus of a point , which is obtained by applying the transformation matrix to the coordinates of (treating as a column vector). Let be the area of the region bounded by , the normal to at its point of local maximum, and the coordinate axes. Find the value of .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Geometric Interpretation|Integration by Parts (LIATE Rule)|Locus Problems via Transformation|Locus of a Moving Point
Why This Question Is Tricky
Examiner Levers
Recursive Logic
The answer to part A is required to solve part B (Step-wise failure test).
Difficulty Boost : +5Common Mistakes
This question tests the intersection of differential equations, locus transformations, and definite integration.
A primary trap lies in the integration by parts of the ODE, where students often fail to define the integration constant as a function of the parameter , leading to an incorrect locus .
Furthermore, the geometric constraint requires identifying the normal at the local maximum of .
Students frequently confuse the normal with the tangent (), which completely alters the bounded region and leads to the distractor option .
The transformation matrix acts as a cognitive pivot, forcing a frame-of-reference shift before the final integration.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Geometric Interpretation |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 170 sec |
| Access | Free |