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Question #67698

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∣x−1∣(x2−px+2)f(x) = |x-1|(x^2 - px + 2), where p∈Rp \in \mathbb{R}. Let p0p_0 be the unique real value of pp for which f(x)f(x) is differentiable at x=1x=1. Let LL be the line of intersection of the planes P1:x+y+z=1P_1: x + y + z = 1 and P2:x+2y+p0z=2P_2: x + 2y + p_0 z = 2. Let SS be the set of all real values of kk such that every point on the line LL satisfies the equation (k−p0)(x+3y+kz)=k2−5k+6(k - p_0)(x + 3y + k z) = k^2 - 5k + 6 Find the sum of all elements in SS.

Options

  • A.

    5

  • B.

    8

  • C.

    3

  • D.

    6

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

System of Linear Equations (Cramer/Inverse)|Line lying in a plane|Cross Multiplication Trap|Right-Hand vs Left-Hand Derivatives

Why This Question Is Tricky

Examiner Levers

Recursive Logic

The answer to part A is required to solve part B (Step-wise failure test).

Difficulty Boost : +5

Common Mistakes

This question tests the 'Cross-Multiplication Trap' (Concept 62) integrated with system dependency and differentiability.

Students must first evaluate RHD and LHD to find p0=3p_0=3.

The core trap lies in the equation (k−3)(x+3y+kz)=(k−3)(k−2)(k-3)(x+3y+kz) = (k-3)(k-2).

Students commonly divide both sides by (k−3)(k-3) to find the plane condition, yielding k=5k=5.

However, by doing so without checking the zero-denominator condition, they implicitly assume k≠3k \neq 3 and lose the singular solution k=3k=3 (where the equation degenerates to the identity 0=00=0, which trivially contains the line).

This forces a rigorous case-by-case analysis of parameters.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterMatrices - Class 12
ConceptSystem of Linear Equations (Cramer/Inverse)
Difficulty8
Cognitive Load7
Target Solve Time170 sec
AccessFree