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Question #66448
The Question
Let be a symmetric orthogonal matrix with continuous entries for all . The trace of is and its first column is given by If , then the value of is
Options
- A.
-4
- B.
4
- C.
-2
- D.
0
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Orthogonal Matrix Conditions|Symmetry and Periodicity|Even and Odd Function Symmetry
Why This Question Is Tricky
Examiner Levers
Recursive Logic
The answer to part A is required to solve part B (Step-wise failure test).
Difficulty Boost : +5Common Mistakes
This question tests the properties of symmetric orthogonal matrices and the exploitation of parity in definite integrals.
The primary trap lies in the implicit definition of the matrix A(x).
Students who attempt to solve for the 9 entries of A(x) using brute-force algebraic equations (A^T A = I) will be overwhelmed.
The elegant path requires recognizing that a symmetric orthogonal matrix with a trace of 1 must be a Householder reflection of the form I - 2uu^T.
Furthermore, a secondary trap awaits during integration: students who fail to identify that the off-diagonal elements involving products of sine and cosine are odd functions will waste significant time integrating them, missing the fact that the integrated matrix B is sparse.
Finally, recognizing that B_11 = 0 completely bypasses the need to integrate A_22, rewarding structural analysis over mechanical calculation.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Matrices - Class 12 |
| Concept | Orthogonal Matrix Conditions |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 170 sec |
| Access | Free |