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Question #66439

Difficulty: 8/10 | 🟢 Free

The Question

Let tnt_n be a non-constant geometric progression of complex numbers with t1=1t_1 = 1. If the system of linear equations in x,y,zx, y, z: t1x+t2y+t3z=0t_1 x + t_2 y + t_3 z = 0 t1x+it2y−t3z=0t_1 x + i t_2 y - t_3 z = 0 t1x+t3y+t5z=0t_1 x + t_3 y + t_5 z = 0 has non-trivial solutions, find the value of ∑n=140nSn\sum_{n=1}^{40} n S_n, where Sn=∑k=1ntkS_n = \sum_{k=1}^n t_k and i=−1i = \sqrt{-1}.

Options

  • A.

    390+410i390 + 410i

  • B.

    410+390i410 + 390i

  • C.

    390−410i390 - 410i

  • D.

    400+400i400 + 400i

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Cramer's Rule Constraints|Selection of GP Terms|Algebraic Manipulation of i

Why This Question Is Tricky

Examiner Levers

Recursive Logic

The answer to part A is required to solve part B (Step-wise failure test).

Difficulty Boost : +5

Common Mistakes

This question tests the application of Cramer's Rule for non-trivial solutions (D=0D=0) combined with complex number algebra.

The primary trap lies in solving the resulting complex quadratic equation r2(i−1)+2r−(1+i)=0r^2(i-1) + 2r - (1+i) = 0.

Students often fail to correctly separate real and imaginary components, leading to incorrect roots for the common ratio rr.

Furthermore, once r=ir=i is found, the secondary cyclic trap requires recognizing the periodicity of SnS_n (period 4) to evaluate the arithmetic-complex-geometric series.

Ignoring this periodicity leads to massive calculation errors.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptCramer's Rule Constraints
Difficulty8
Cognitive Load7
Target Solve Time170 sec
AccessFree