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Question #61719

Difficulty: 5/10 | 🟢 Free

The Question

Let M(x)=[sin⁡−1(x)cos⁡−1(x)π2x2x3x2x22x3x2(2x+1)]M(x) = \begin{bmatrix} \sin^{-1}(x) & \cos^{-1}(x) & \frac{\pi}{2} \\ x & 2x & 3x \\ 2x^2 & 2x & \frac{3x}{2}(2x+1) \end{bmatrix} and A(x)=xM(x)A(x) = x M(x). If F(x)=det⁡(A(x))F(x) = \det(A(x)), which of the following statements is INCORRECT?

Options

  • A.

    F′(12)=0F'\left(\frac{1}{2}\right) = 0

  • B.

    adj(M(12))\text{adj}\left(M\left(\frac{1}{2}\right)\right) is a non-zero matrix

  • C.

    F′′(12)=38F''\left(\frac{1}{2}\right) = \frac{\sqrt{3}}{8}

  • D.

    F(x)F(x) attains a local minimum at x=12x = \frac{1}{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Derivative of Implicit Inverse Forms|Differentiation of Determinants|Determinant Scaling Property|Singular vs Non-Singular Matrices

Why This Question Is Tricky

Examiner Levers

Negative Thinking

Uses "NOT", "EXCEPT", or "INCORRECT" to flip the logic gate.

Difficulty Boost : +2

Common Mistakes

This question tests the intersection of determinant scaling properties and the derivative of determinants via the adjugate matrix.

Students often fall into the trap of attempting brute-force row-wise differentiation of the complex inverse trigonometric matrix.

The 'Lethal Collision' occurs because scaling the matrix by xx requires applying det⁡(xM)=x3det⁡(M)\det(xM) = x^3\det(M), and evaluating the derivative at x=1/2x=1/2 relies on recognizing that M(1/2)M(1/2) has a rank of 1.

A rank 1 matrix has a zero adjugate, which instantly collapses the derivative of its determinant to zero (via Jacobi's formula ddxdet⁡(M)=tr(adj(M)M′)\frac{d}{dx}\det(M) = \text{tr}(\text{adj}(M)M')), bypassing the need for tedious expansion while simultaneously proving that the adjugate is a zero matrix.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterInverse Trigonometric Functions - Class 12
ConceptDerivative of Implicit Inverse Forms
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree