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Question #51613

Difficulty: 5/10 | 🟢 Free

The Question

Let SS be the set of all real numbers aa such that the function f(x)=(x2−1)(x−3)2∣x−1∣(x+1)(x−3)(x−5)f(x) = \frac{(x^2-1)(x-3)^2}{|x-1|(x+1)(x-3)(x-5)} is discontinuous at x=ax=a, but lim⁡x→af(x)\lim_{x \to a} f(x) exists. Let g:[0,3]→Rg: [0, 3] \to \mathbb{R} be defined by g(x)=x3−3x2+2g(x) = x^3 - 3x^2 + 2. Let TT be the set of all integers kk such that the equation g(x)=kg(x) = k has more than one distinct real solution. Find the sum of the elements in the set SΔTS \Delta T, where SΔTS \Delta T denotes the symmetric difference of sets SS and TT.

Options

  • A.

    4

  • B.

    5

  • C.

    6

  • D.

    7

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Difference vs. Symmetric Difference|Bijectivity and Inverse|Limit Existence at Discontinuity

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between removable and non-removable discontinuities, and their understanding of symmetric difference.

The primary trap lies in evaluating the limit at x=1x=1 and x=−1x=-1 for f(x)f(x); students often incorrectly assume that the presence of an absolute value ∣x−1∣|x-1| implies the limit does not exist at x=−1x=-1, or they fail to check the left and right-hand limits at x=1x=1.

Additionally, when finding set TT, students might incorrectly include k=−2k=-2 (which only has one solution at the local minimum) or exclude k=2k=2 (which has two solutions at the boundary and local maximum), leading to an incorrect symmetric difference computation.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSets - Class 11
ConceptDifference vs. Symmetric Difference
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree