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Question #51587

Difficulty: 8/10 | 🟢 Free

The Question

Let AA be a 2n×2n2n \times 2n skew-symmetric matrix with real entries. Assume that for any subset I⊂{1,2,…,2n}I \subset \{1, 2, \dots, 2n\} with ∣I∣=n|I| = n, the n×nn \times n submatrix AI,IcA_{I, I^c} (formed by the rows indexed by II and columns indexed by Ic={1,2,…,2n}∖II^c = \{1, 2, \dots, 2n\} \setminus I) is non-singular. Define f(n)=∏∣I∣=ndet⁡(AI,Ic)f(n) = \prod_{|I|=n} \det(A_{I, I^c}). Let Sn∈{+,−}S_n \in \{+, -\} denote the sign of f(n)f(n). Which of the following represents the sequence (S1,S2,S3,S4)(S_1, S_2, S_3, S_4)?

Options

  • A.

    (−,+,−,+)(-, +, -, +)

  • B.

    (−,+,+,+)(-, +, +, +)

  • C.

    (+,+,−,−)(+, +, -, -)

  • D.

    (−,−,+,+)(-, -, +, +)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Set Complement Boundaries|Row/Column Exchange Parity|Determinant Product Rule

Why This Question Is Tricky

Examiner Levers

Negative Thinking

Uses "NOT", "EXCEPT", or "INCORRECT" to flip the logic gate.

Difficulty Boost : +2

Logical Assertion

Tests the causal relationship between two true statements.

Difficulty Boost : +4

Recursive Logic

The answer to part A is required to solve part B (Step-wise failure test).

Difficulty Boost : +5

Common Mistakes

This question tests the properties of determinants under set complement boundaries and row/column parity shifts.

The core trap lies in the assumption that the sign of the product alternates with nn (i.e., (−1)n(-1)^n).

Students correctly identify that swapping II and IcI^c introduces a (−1)n(-1)^n factor, but fail to account for the recursive logic that the total sign depends on the number of complementary pairs, k=12(2nn)k = \frac{1}{2}\binom{2n}{n}.

Because kk grows non-linearly and is even for all n≥2n \ge 2, the parity shift collapses, resulting in a positive product for n=3n=3 despite nn being odd.

This exposes a lethal collision between local sign changes and global combinatorial parity.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSets - Class 11
ConceptSet Complement Boundaries
Difficulty8
Cognitive Load8
Target Solve Time180 sec
AccessFree