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Question #47745
The Question
Temperature manipulation is a critical step in both the Polymerase Chain Reaction (PCR) and the transformation of competent bacterial cells. Which of the following accurately contrasts the physiological basis of thermal interaction in these two distinct biotechnological procedures?
Options
- A.
Taq polymerase maintains its active site conformation at 94°C due to thermostable bonds, whereas the 42°C heat shock transiently alters the lipid bilayer fluidity to create physical pores for DNA entry.
- B.
The 94°C step in PCR facilitates the optimal polymerization activity of Taq polymerase, while the 42°C heat shock denatures bacterial surface proteins to allow plasmid integration.
- C.
Both procedures utilize thermal stress to alter protein structures; PCR activates the Taq enzyme, while heat shock activates DNA-binding proteins on the bacterial cell wall.
- D.
Taq polymerase resists denaturation at 94°C to allow primer annealing, whereas the 42°C heat shock increases the kinetic energy of the plasmid for active transport across the membrane.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Evolutionary_Exception
Tackle problems where standard rules evolve or change based on specific environmental constraints.
Concepts Behind This Question
Repetitive_DNA|Gel_Electrophoresis|Elution
Why This Question Is Tricky
Common Mistakes
Conceptual Pivot: Distinguishing between the thermal stability of proteins (Taq polymerase kinetics) and thermal-induced physical membrane fluidization (competent cell transformation).
The trap relies on students confusing the purpose of heat in different biotech steps—assuming heat always denatures/activates proteins, or mixing up the specific temperature optimums of PCR steps (Denaturation at 94°C vs Extension at 72°C).
Quick Facts About This Question
Question Information
| Subject | Biology |
| Chapter | Biotechnology : Principles and Processes - Class 12 |
| Concept | Elution Process |
| Difficulty | 8 |
| Cognitive Load | 5 |
| Target Solve Time | 120 sec |
| Access | Free |